Students of Grade 3 Module 3 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

## Engage NY Eureka Math 3rd Grade Module 3 Lesson 6 Answer Key

So teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

### Eureka Math Grade 3 Module 3 Lesson 6 Pattern Sheet Answer Key

Multiply

Answer:

6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 10 = 60, 6 x 5 = 30, 6 x 6 = 36, 6 x 5 = 30, 6 x 7 = 35, 6 x 5 = 30, 6 x 8 = 40, 6 x 5 = 30, 6 x 9 = 54, 6 x 5 = 30, 6 x 10 = 60, 6 x 6 = 36, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 7 = 42, 6 x 9 = 54, 6 x 7 = 42, 6 x 8 = 48, 6 x 6 = 36, 6 x 8 = 48, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 9 = 54, 6 x 6 = 36, 6 x 9 = 54, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 6 = 36, 6 x 8 = 48, 6 x 9 = 54, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48.

Explanation:

In the above-given question,

given that,

the table of 6.

6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 10 = 60, 6 x 5 = 30, 6 x 6 = 36, 6 x 5 = 30, 6 x 7 = 35, 6 x 5 = 30, 6 x 8 = 40, 6 x 5 = 30, 6 x 9 = 54, 6 x 5 = 30, 6 x 10 = 60, 6 x 6 = 36, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 7 = 42, 6 x 9 = 54, 6 x 7 = 42, 6 x 8 = 48, 6 x 6 = 36, 6 x 8 = 48, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 9 = 54, 6 x 6 = 36, 6 x 9 = 54, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 6 = 36, 6 x 8 = 48, 6 x 9 = 54, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48.

### Eureka Math Grade 3 Module 3 Lesson 6 Problem Set Answer Key

Question 1.

Label the tape diagrams. Then, fill in the blanks below to make the statements true.

a. 6 Ã— 6 = __36___

(6 Ã— 6) = (5 + 1) Ã— 6

= (5 Ã— 6) + (1 Ã— 6)

=Â Â 30Â Â + __6____

= ____6__

Answer:

5 x 6 = 30.

1 x 6 = 6.

30 + 6 = 36.

Explanation:

In the above-given question,

given that,

6 x 6 = (5 + 1) x 6.

(5 x 6) + (1 x 6).

30 + 6.

36.

b. 7 Ã— 6 = __42___

(7 Ã— 6) = (5 + 2) Ã— 6

= (5 Ã— 6) + (2 Ã— 6)

=Â Â 30Â Â Â + __12____

= ____42__

Answer:

5 x 6 = 30.

2 x 6 = 12.

30 + 12 = 42.

Explanation:

In the above-given question,

given that,

7 x 6 = (5 + 2) x 6.

(5 x 6) + (2 x 6).

30 + 12.

42.

c. 8 Ã— 6 = ___48__

8 Ã— 6 = (5 + ___3__ ) Ã— 6

= (5 Ã— 6) + ( __3__ Ã— 6)

=Â Â 30Â Â + __18____

= __48____

Answer:

5 x 6 = 30.

3 x 6 = 18.

30 + 18 = 48.

Explanation:

In the above-given question,

given that,

8 x 6 = (5 + 3) x 6.

(5 x 6) + (3 x 6).

30 + 18.

48.

d. 9 Ã— 6 = __54___

9 Ã— 6 = (5 + __4___ ) Ã— 6

= (5 Ã— 6) + ( _4___ Ã— 6)

=Â Â 30Â Â + __24____

= __54____

Answer:

5 x 6 = 30.

4 x 6 = 24.

30 + 24 = 54.

Explanation:

In the above-given question,

given that,

9 x 6 = (5 + 4) x 6.

(5 x 6) + (4 x 6).

30 + 24.

54.

Question 2.

Break apart 54 to solve 54 Ã· 6.

54 Ã· 6 = (30 Ã· 6) + ( __24________ Ã· 6)

= 5 + ______4______

= ____9_______

Answer:

54 / 6 = 9.

Explanation:

In the above-given question,

given that,

54 / 6 is divided into two parts.

30 / 6 and 24 / 6.

30 / 6 = 5 and 24 / 6 = 4.

5 + 4 = 9.

Question 3.

Break apart 49 to solve 49 Ã· 7.

49 Ã· 7 = (35 Ã· 7) + ( ___14_______ Ã· 7)

= 5 + _______2_____

= _____7______

Answer:

49 / 7 = 7.

Explanation:

In the above-given question,

given that,

49 / 7 is divided into two parts.

35 / 7 and 14 / 7.

35 / 7 = 5 and 14 / 7 = 2.

5 + 2 = 7.

Question 4.

Robert says that he can solve 6 Ã— 8 by thinking of it as (5 Ã— 8) + 8. Is he right? Draw a picture to help explain your answer.

Answer:

Yes, he was right.

Explanation:

In the above-given question,

given that,

Robert says that he can solve 6 x 8 by thinking of it as (5 x 8) + 8.

6 x 8 = 48.

(5 x 8) + 8 = 40 + 8 = 48.

so he was correct.

Question 5.

Kelly solves 42 Ã· 7 by using a number bond to break apart 42 into two parts. Show what her work might look like below.

Answer:

42 / 7 = 6.

Explanation:

In the above-given question,

given that,

42 / 7 is divided into two parts.

28 / 7 and 14 / 7.

28 / 7 = 4 and 14 / 7 = 2.

4 + 2 = 6.

### Eureka Math Grade 3 Module 3 Lesson 6 Exit Ticket Answer Key

Question 1.

A parking lot has space for 48 cars. Six cars can park in 1 row. Break apart 48 to find how many rows there are in the parking lot.

Answer:

48 / 6 = 8.

Explanation:

In the above-given question,

given that,

48 / 6 is divided into two parts.

30 / 6 and 18 / 6.

30 / 6 = 5 and 18 / 6 = 3.

5 + 3 = 8.

Question 2.

Malia solves 6 Ã— 7 using (5 Ã— 7) + 7. Leonidas solves 6 Ã— 7 using (6 Ã— 5) + (6 Ã— 2). Who is correct? Draw a picture to help explain your answer.

Answer:

Yes, both of them are correct.

Explanation:

In the above-given question,

given that,

6 x 7 = 42.

(5 x 7) + 7 = 35 + 7 = 42.

(6 x 5) + (6 x 2) = 30 + 12 = 42.

### Eureka Math Grade 3 Module 3 Lesson 6 Homework Answer Key

Question 1.

Label the tape diagrams. Then, fill in the blanks below to make the statements true.

a. 6 Ã— 7 = __42___

(6 Ã— 7) = (5 + 1) Ã— 7

= (5 Ã— 7) + (1 Ã— 7)

=Â Â 35Â Â Â + ___7___

= ___42___

Answer:

5 x 7 = 35.

1 x 7 = 7.

35 + 7 = 42.

Explanation:

In the above-given question,

given that,

6 x 7 = (5 + 1) x 7.

(5 x 7) + (1 x 7).

35 + 7.

42.

b. 7 Ã— 7 = __49___

(7 Ã— 7) = (5 + 2) Ã— 7

= (5 Ã— 7) + (2 Ã— 7)

=Â Â 35Â Â Â + __14___

= ___49___

Answer:

5 x 7 = 35.

2 x 7 = 14.

35 + 14 = 49.

Explanation:

In the above-given question,

given that,

6 x 7 = (5 + 2) x 7.

(5 x 7) + (2 x 7).

35 + 14.

49.

c. 8 Ã— 7 = __56___

8 Ã— 7 = (5 + ___3__ ) Ã— 7

= (5 Ã— 7) + ( __3__ Ã— 7)

=Â Â 35Â Â Â + ___21___

= __56____

Answer:

5 x 7 = 35.

3 x 7 = 21.

35 + 21 = 56.

Explanation:

In the above-given question,

given that,

8 x 7 = (5 + 3) x 7.

(5 x 7) + (3 x 7).

35 + 21.

56.

d. 9 Ã— 7 = __63___

9 Ã— 7 = (5 + __4___ ) Ã— 7

= (5 Ã— 7) + ( __4__ Ã— 7)

=Â Â 35Â Â + ___28___

= ___63___

Answer:

5 x 7 = 35.

4 x 7 = 28.

35 + 28 = 63.

Explanation:

In the above-given question,

given that,

9 x 7 = (5 + 4) x 7.

(5 x 7) + (4 x 7).

35 + 28.

63.

Question 2.

Break apart 54 to solve 54 Ã· 6.

54 Ã· 6 = (30 Ã· 6) + ( ____24_______ Ã· 6)

= 5 + _______4_____

= _____9______

Answer:

54 / 6 = 9.

Explanation:

In the above-given question,

given that,

54 / 6 is divided into two parts.

30 / 6 and 24 / 6.

30 / 6 = 5 and 24 / 6 = 4.

5 + 4 = 9.

Question 3.

Break apart 56 to solve 56 Ã· 7

56 Ã· 7 = ( __35___ Ã· ___7__ ) + ( __21___ Ã· ___7__ )

= 5 + ____3____

= ____8______

Answer:

56 / 7 = 8.

Explanation:

In the above-given question,

given that,

56 / 7 is divided into two parts.

35 / 7 and 21 / 7.

35 / 7 = 5 and 21 / 7 = 3.

5 + 3 = 8.

Question 4.

Forty-two third grade students sit in 6 equal rows in the auditorium. How many students sit in each row? Show your thinking.

Answer:

The number of students sits in each row = 7.

Explanation:

In the above-given question,

given that,

42 third-grade students sit in 6 equal rows in the auditorium.

42 / 6 = 7.

7 x 6 = 42.

Question 5.

Ronaldo solves 7 Ã— 6 by thinking of it as (5 Ã— 7) + 7. Is he correct? Explain Ronaldoâ€™s strategy.

Answer:

Yes, he was correct.

Explanation:

In the above-given question,

given that,

Ronaldo solves 7 x 6 = 42.

(5 x 7) + 7 = 42.

so he was correct.