Eureka Grade 3 ensures students with the learning targets and success criteria. The Diverse opportunities will develop problem-solving skills among the primary school kids practicing Bigideas Math Grade 3 Solutions. Eureka Textbook Grade 3 answers help Students Master the subject on Consistent practice.

## Engage NY Eureka Math 3rd Grade Module 3 Lesson 20 Answer Key

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

### Eureka Math Grade 3 Module 3 Lesson 20 Problem Set Answer Key

Question 1.
Use the chart to complete the equations. Then, solve. The first one has been done for you.
a.

(2 Ã— 4) Ã— 10
= (8 ones) Ã— 10
= ___80____

8 x 10 = 80.

Explanation:
In the above-given question,
given that,
(2 x 4) x 10.
(8 ones) x 10.
80.

b.

2 Ã— (4 Ã— 10)
= 2 Ã— (4 tens)
= ___80____

2 x 4 tens = 80.

Explanation:
In the above-given question,
given that,
2 x (4 x 10).
2 x (4 tens).
80.

c.

(3 Ã— 5) Ã— 10
= ( __15___ ones ) Ã— 10
= ___150____

15 x 10 = 150.

Explanation:
In the above-given question,
given that,
(3 x 5) x 10.
(15 ones) x 10.
150.

d.

3 Ã— (5 Ã— 10)
= 3 Ã— ( ___50___ tens)
= ___150____

3 x 5 tens = 150.

Explanation:
In the above-given question,
given that,
3 x (5 x 10).
3 x (5 tens).
150.

Question 2.
Place parentheses in the equations to find the related fact. Then, solve. The first one has been done for you.

2 x 20 = 40.
2 x 30 = 60.
3 x 30 = 90.
2 x 50 = 100.

Explanation:
In the above-given figure,
given that,
2 x 20 = 2 x (2 x 10).
(2 x 2) x 10.
4 x 10 = 40.
2 x 30 = 2 x (3 x 10).
(2 x 3) x 10.
6 x 10 = 60.
3 x 30 = 3 x (3 x 10).
(3 x 3) x 10.
9 x 10 = 90.
2 x 50 = 2 x (5 x 10).
(2 x 5) x 10.
10 x 10 = 100.

Question 3.
Gabriella solves 20 Ã— 4 by thinking about 10 Ã— 8. Explain her strategy.

20 x 4 = 80.

Explanation:
In the above-given question,
given that,
Gabriella solves 20 x 4 = 80.
This can also write it as 10 x 8 = 80.
20 x 4 = (2 x 10) x 4.
2 x (10 x 4).
2 x 40 = 80.

### Eureka Math Grade 3 Module 3 Lesson 20 Exit Ticket Answer Key

Question 1.
Place parentheses in the equations to find the related fact. Then, solve.
a. 4 Ã— 20 = 4 Ã— 2 Ã— 10
= 4 Ã— 2 Ã— 10
= __8____ Ã— 10
= __80____

4 x 20 = 80.

Explanation:
In the above-given question,
given that,
4 x 20 = 4 x (2 x 10).
(4 x 2) x 10.
8 x 10.
80

b. 3 Ã— 30 = 3 Ã— 3 Ã— 10
= 3 Ã— 3 Ã— 10
= __9___ Ã— 10

3 x 30 = 90.

Explanation:
In the above-given question,
given that,
3 x 30 = 3 x (3 x 10).
(3 x 3) x 10.
9 x 10.
90

Question 2.
Jamila solves 20 Ã— 5 by thinking about 10 tens. Explain her strategy.

20 x 5 = 100.

Explanation:
In the above-given question,
given that,
Jamila solves 20 x 5 by thinking about 10 tens.
20 x 5 = (2 x 10) x 5.
2 x (10 x 5).
2 x 50 = 100.
10 x 10 = 100.

### Eureka Math Grade 3 Module 3 Lesson 20 Homework Answer Key

Question 1.
Use the chart to complete the equations. Then, solve.
a.

(2 Ã— 5) Ã— 10
= (10 ones) Ã— 10
= ___100____

8 x 10 = 80.

Explanation:
In the above-given question,
given that,
(2 x 5) x 10.
(10 ones) x 10.
100.

b.

2 Ã— (5 Ã— 10)
= 2 Ã— (5 tens)
= ___100____

2 x 5 tens = 100.

Explanation:
In the above-given question,
given that,
2 x (5 x 10).
2 x (5 tens).
100.

c.

(4 Ã— 5) Ã— 10
= (__20___ ones) Ã— 10
= ___200____

20 x 10 = 200.

Explanation:
In the above-given question,
given that,
(4 x 5) x 10.
(20 ones) x 10.
200.

d.

4 Ã— (5 Ã— 10)
= 4 Ã— (__5__ tens)
= ___200____

4 x 5 tens = 200.

Explanation:
In the above-given question,
given that,
4 x (5 x 10).
4 x (5 tens).
200.

Question 2.
Solve, Place parentheses in (c) and (d) as needed to find the related fact.

3 x 20 = 60.
3 x 30 = 90.
3 x 40 = 120.
3 x 50 = 150.

Explanation:
In the above-given figure,
given that,
3 x 20 = 3 x (2 x 10).
(3 x 2) x 10.
6 x 10 = 60.
3 x 30 = 3 x (3 x 10).
(3 x 3) x 10.
9 x 10 = 90.
3 x 40 = 3 x (4 x 10).
(3 x 4) x 10.
12 x 10 = 120.
3 x 50 = 3 x (5 x 10).
(3 x 5) x 10.
15 x 10 = 150.

Question 3.
Danny solves 5 Ã— 20 by thinking about 10 Ã— 10. Explain his strategy.