Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.

## Engage NY Eureka Math 3rd Grade Module 3 Lesson 12 Answer Key

Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.

### Eureka Math Grade 3 Module 3 Lesson 12 Pattern Sheet Answer Key

Multiply

Answer:

8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 10 = 80, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 8 = 64, 8 x 5 = 40, 8 x 9 = 72, 8 x 5 = 40, 8 x 10 = 80, 8 x 6 = 48, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 7 = 56, 8 x 9 = 72, 8 x 7 = 56, 8 x 8 = 64, 8 x 6 48, 8 x 8 = 64, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 9 = 72, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 8 = 64, 8 x 9 = 72, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 6 = 48, 8 x 8 = 64, 8 x 9 = 72, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64.

Explanation:

In the above-given question,

given that,

the table of 8 and multiply.

8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 10 = 80, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 8 = 64, 8 x 5 = 40, 8 x 9 = 72, 8 x 5 = 40, 8 x 10 = 80, 8 x 6 = 48, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 7 = 56, 8 x 9 = 72, 8 x 7 = 56, 8 x 8 = 64, 8 x 6 48, 8 x 8 = 64, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 9 = 72, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 8 = 64, 8 x 9 = 72, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 6 = 48, 8 x 8 = 64, 8 x 9 = 72, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64.

### Eureka Math Grade 3 Module 3 Lesson 12 Problem Set Answer Key

Question 1.

Each has a value of 9. Find the value of each row. Then, add the rows to find the total.

a. 6 Ã— 9 = ___54____

6 Ã— 9 = (5 + 1) Ã— 9

= (5 Ã— 9) + (1 Ã— 9)

= 45 + ___9__

= __54___

Answer:

6 x 9 = 54.

Explanation:

In the above-given question,

given that,

6 x 9 = ( 5 + 1 ) x 9.

( 5 x 9 ) + ( 1 x 9 )

45 + 9

54.

b. 7 Ã— 9 = ____63___

7 Ã— 9 = (5 + __2__) Ã— 9

= (5 Ã— 9) + (__2__ Ã— 9)

= 45 + __18___

= ___63__

Answer:

7 x 9 = 63.

Explanation:

In the above-given question,

given that,

7 x 9 = ( 5 + 2 ) x 9.

( 5 x 9 ) + ( 2 x 9 )

45 + 18.

63.

c. 8 Ã— 9 = ___72____

8 Ã— 9 = (5 + ___3__) Ã— 9

= (5 Ã— 9) + (___3__ Ã— __9___)

= 45 + __27___

= __72___

Answer:

8 x 9 = 72.

Explanation:

In the above-given question,

given that,

8 x 9 = ( 5 + 3 ) x 9.

( 5 x 9 ) + ( 3 x 9 )

45 + 27.

72.

d. 9 Ã— 9 = ____81___

9 Ã— 9 = (5 + ___4__) Ã— 9

= (5 Ã— 9) + (__4___ Ã— ___9__)

= 45 + __36___

= __81___

Answer:

9 x 9 = 81.

Explanation:

In the above-given question,

given that,

9 x 9 = ( 5 + 4 ) x 9.

( 5 x 9 ) + ( 4 x 9 )

45 + 36.

81.

Question 2.

Find the total value of the shaded blocks.

a. 9 Ã— 6 = 54

9 sixes = 10 sixes â€“ 1 six

=__60___ â€“ 6

= __54___

Answer:

9 x 6 = 54.

Explanation:

In the above-given equation,

given that,

9 sixes = 10 sixes – 1 six.

60 – 6.

54.

b. 9 Ã— 7 = 63

9 sevens = 10 sevens â€“ 1 seven

= __70___ â€“ 7

= __63___

Answer:

9 x 7 = 63.

Explanation:

In the above-given equation,

given that,

9 sevens = 10 sevens – 1 seven.

70 – 7.

63.

c. 9 Ã— 8 = 72.

9 eights = 10 eights â€“ 1 eight

= __80___ â€“ 8

= __72___

Answer:

9 x 8 = 72.

Explanation:

In the above-given equation,

given that,

9 eights = 10 eights – 1 eight.

80 – 8.

72.

d. 9 Ã— 9 = 81.

9 nines = 10 nines â€“ 1 nine

= __90___ â€“ __9___

= __81___

Answer:

9 x 9 = 81.

Explanation:

In the above-given equation,

given that,

9 nines = 10 nines – 1 nine.

90 – 9.

81.

Question 3.

Matt buys a pack of postage stamps. He counts 9 rows of 4 stamps. He thinks of 10 fours to find the total number of stamps. Show the strategy that Matt might have used to find the total number of stamps.

Answer:

9 x 4 = 36.

Explanation:

In the above-given equation,

given that,

9 fours = 10 fourss – 1 four.

40 – 4.

36.

Question 4.

Match

Answer:

3 x 9 = 27, 45 / 9 = 5.

9 x 9 = 81, 9 / 9 = 1.

8 x 9 = 72, 90 / 9 = 10.

9 x 4 = 36, 72 / 9 = 8.

2 x 9 = 18, 54 / 9 = 6.

Explanation:

In the above-given question,

given that,

the multiplication and division of 9.

3 x 9 = 27, 45 / 9 = 5.

9 x 9 = 81, 9 / 9 = 1.

8 x 9 = 72, 90 / 9 = 10.

9 x 4 = 36, 72 / 9 = 8.

2 x 9 = 18, 54 / 9 = 6.

### Eureka Math Grade 3 Module 3 Lesson 12 Exit Ticket Answer Key

Question 1.

Each has a value of 9. Complete the equations to find the total value of the tower of blocks.

___5__ Ã— 9 = (5 + __1__ ) Ã— 9

= (5 Ã— ___9__ ) + ( __1___ Ã— __9___ )

= 45 + __9___

= __54___

Answer:

6 x 9 = 54.

Explanation:

In the above-given question,

given that,

5 x 9 = ( 5 + 1 ) x 9.

( 5 x 9 ) + ( 1 x 9 )

45 + 9.

54.

Question 2.

Hector solves 9 Ã— 8 by subtracting 1 eight from 10 eights. Draw a model, and explain Hectorâ€™s strategy.

Answer:

9 x 8 = 72.

Explanation:

In the above-given question,

given that,

9 x 8 = 72.

10 eights – 1 eight.

80 – 8.

72.

Eureka Math Grade 3 Module 3 Lesson 12 Homework Answer Key

Question 1.

Find the value of each row. Then, add the rows to find the total.

a. Each has a value of 6.

9 Ã— 6 = ___54_____

9 Ã— 6 = (5 + 4) Ã— 6

= (5 Ã— 6) + (4 Ã— 6)

= 30 + __24___

= __54___

Answer:

6 x 9 = 54.

Explanation:

In the above-given question,

given that,

6 x 9 = ( 5 + 4 ) x 6.

( 5 x 6 ) + ( 4 x 6 )

30 + 24.

54.

b. Each has a value of 7.

9 Ã— 7 = ___63_____

9 Ã— 7 = (5 + __4___) Ã— 7

= (5 Ã— 7) + (__4___ Ã— 7)

= 35 + __28___

= ___63__

Answer:

9 x 7 = 63.

Explanation:

In the above-given question,

given that,

9 x 7 = ( 5 + 4 ) x 7.

( 5 x 7 ) + ( 4 x 9 )

35 + 28.

63.

c. Each has a value of 8.

9 Ã— 8 = ____72____

9 Ã— 8 = (5 + __4___) Ã— 8

= (5 Ã— 8) + (__4___ Ã— ___8__)

= 40 + ___32__

= __72___

Answer:

9 x 8 = 72.

Explanation:

In the above-given question,

given that,

9 x 8 = ( 5 + 4 ) x 8.

( 5 x 8 ) + ( 4 x 8 )

40 + 32.

72.

d. Each has a value of 9.

9 Ã— 9 = ____81____

9 Ã— 9 = (5 + _____) Ã— 9

= (5 Ã— 9) + (__4___ Ã— __9___)

= 45 + ___36__

= __81___

Answer:

9 x 9 = 81.

Explanation:

In the above-given question,

given that,

9 x 9 = ( 5 + 4 ) x 9.

( 5 x 9 ) + ( 4 x 9 )

45 + 36.

81.

Question 2.

Match

Answer:

50 – 5 = 45, 9 x 5 = 45.

60 – 6 = 54, 9 x 6 = 54.

70 – 7 = 63, 9 x 7 = 63.

80 – 8 = 72, 9 x 8 = 72.

90 – 9 = 81, 9 x 9 = 81.

40 – 4 = 36, 9 x 4 = 36.

Explanation:

In the above-given question,

given that,

the multiplication and division of 9 is given.

50 – 5 = 45, 9 x 5 = 45.

60 – 6 = 54, 9 x 6 = 54.

70 – 7 = 63, 9 x 7 = 63.

80 – 8 = 72, 9 x 8 = 72.

90 – 9 = 81, 9 x 9 = 81.

40 – 4 = 36, 9 x 4 = 36.