## Engage NY Eureka Math 3rd Grade Module 1 Lesson 6 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 6 Problem Set Answer Key

Question 1.

Rick puts 15 tennis balls into cans. Each can holds 3 balls.

Circle groups of 3 to show the balls in each can.

Rick needs ____5___ cans.

___5___ Ã— 3 = 15

15 Ã· 3 = __5____

Explanation:

Given Rick puts 15 tennis balls into cans and each can holds 3 balls. Circled groups of 3 to show the balls in each can.

Rick needs 15 Ã· 3 = 5, 5 Ã— 3 = 15,

Therefore Rick needs 5 cans.

Question 2.

Rick uses 15 tennis balls to make 5 equal groups.

Draw to show how many tennis balls are in each group.

There are ____3___ tennis balls in each group.

5 Ã— __3____ = 15

15 Ã· 5 = ___3___

Answer:

There are 3 tennis balls in each group.

Explanation:

Given Rick uses 15 tennis balls to make 5 equal groups.

Drawn circles to show 3 number of tennis balls are in each group as 15 Ã· 5 = 3, 5 Ã— 3 = 15,

Therefore, there are 3 tennis balls in each group.

Question 3.

Use an array to model Problem 1.

a. ___5___ Ã— 3 = 15

15 Ã· 3 = ___5___

The number in the blanks represents

_____5 groups___________________.

Explanation:

Used an array to model Problem 1 as

5 Ã— 3 = 15 or 15 Ã· 3 = 5,

The number in the blanks represents groups as

5 groups of balls.

b. 5 Ã— __3____ = 15

15 Ã· 5 = __3____

The number in the blanks represents

____________3 balls in each group________.

Answer:

The number in the blanks represents 3 balls in each group,

Explanation:

Rick uses 15 tennis balls to make 5 equal groups,

15 Ã· 5 = 3 or 5 Ã— 3= 15, The number in the blanks

represents 3 balls in each group.

Question 4.

Deena makes 21 jars of tomato sauce. She puts 7 jars in

each box to sell at the market. How many boxes does Deena need?

21 Ã· 7 = __3____

___3___ Ã— 7 = 21

What is the meaning of the unknown factor and quotient?

_________3______________

Answer:

Deena needs 3 boxes,

Explanation:

Given Deena makes 21 jars of tomato sauce and she puts 7 jars in each box to sell at the market.

So number of boxes Deena needs are 21 Ã· 7 = 3, (3 Ã— 7 = 21)

Therefore, Deena needs 3 boxes.

Question 5.

The teacher gives the equation 4 Ã— __3__ = 12. Charlie finds the answer by writing and solving 12 Ã· 4 = __3__.

Explain why Charlieâ€™s method works.

Answer:

Charlie method is 12 Ã· 4 = 3,

Explanation:

Given The teacher gives the equation 4 Ã— ____ = 12.

Charlie finds the answer by writing and solving as

12 Ã· 4 = 3,

because multiplication and divisionÂ are closely related,

given thatÂ divisionÂ is the inverse operation ofÂ multiplication.

When weÂ divide, we look to separate into equal groups,

whileÂ multiplication involves joining equal groups.

If we divideÂ this product by one of the factors,

we get the other factor as a result. So Charlie uses division method to solve missing factor in the given equation as 3. So the equation is 4 X 3 = 12.

Question 6.

The blanks in Problem 5 represent the size of the groups.

Draw an array to represent the equations.

Explanation:

Drawn an array that represents the equations asÂ 4 Ã— 3 = 12.

### Eureka Math Grade 3 Module 1 Lesson 6 Exit Ticket Answer Key

Cesar arranges 12 notecards into rows of 6 for his presentation.

Draw an array to represent the problem.

12 Ã· 6 = ___2_____

____2____ Ã— 6 = 12

What do the unknown factor and quotient represent?

___2 notecards in each row____

Explanation:

Given Cesar arranges 12 notecards into rows of 6 for his presentation.

Drawn an array to represent the problem as 12 Ã· 6 = 2, 2 Ã— 6 = 12, means 6 rowsÂ and 2 columns as shown above, The unknown factor and quotient 2

represents 2 notecards in each row.

### Eureka Math Grade 3 Module 1 Lesson 6 Homework Answer Key

Question 1.

Mr. Hannigan puts 12 pencils into boxes. Each box holds 4 pencils.

Circle groups of 4 to show the pencils in each box.

Mr. Hannigan needs ___3____ boxes.

___3___ Ã— 4 = 12

12 Ã· 4 = __3____

Mr. Hannigan needs 3 boxes,

Explanation:

Given Mr. Hannigan puts 12 pencils into boxes.

Each box holds 4 pencils.

Circled groups of 4 to show the pencils in each box as shown above, So Mr. Hannigan needs 12 Ã· 4 = 3 boxes,

( 3 x 4 = 12).

Question 2.

Mr. Hannigan places 12 pencils into 3 equal groups.

Draw to show how many pencils are in each group.

There are ___4____ pencils in each group.

3 Ã— ___4___ = 12

12 Ã· 3 = ___4___

There are 4 pencils in each group,

Explanation:

Given Mr. Hannigan places 12 pencils into 3 equal groups,

Drawn to show 4 number of pencils are in each group as 12 Ã· 3 = 4, 3 Ã— 4 = 12, Therefore 4 pencils are there in each group.

Question 3.

Use an array to model Problem 1.

a. ___3___ Ã— 4 = 12

12 Ã· 4 = ___3___

The number in the blanks represents

___________3 groups______________.

a.

The number in the blanks represents 3 groups,

Explanation:

Used an array to model Problem 1 as 3 x 4 = 12, or 12 Ã· 4 = 3, therefore the number in the blanks represents 3 groups.

b. 3 Ã— ___4___ = 12

12 Ã· 3 = __4____

The number in the blanks represents

___________4 pencils in each group_____________.

Answer:

The number in the blanks represents 4 pencils in each group,

Explanation:

Given Mr. Hannigan places 12 pencils into 3 equal groups.

12 Ã· 3 = 4 or 3 Ã— 4= 12, The number in the blanks represents 4 pencils in each group.

Question 4.

Judy washes 24 dishes. She then dries and stacks the dishes equally into 4 piles. How many dishes are in each pile?

24 Ã· 4 = ___6____

4 Ã— ___6_____ = 24

What is the meaning of the unknown factor and quotient?

__________6 dishes are in each pile____________________

Answer:

There are 6 dishes in each pile,

Explanation:

Given Judy washes 24 dishes and she then dries and stacks the dishes equally into 4 piles.

So number of dishes in each pile are 24 Ã· 4 = 6, or 4 Ã— 6 = 24, The meaning of the unknown factor and quotient is 6 dishes are there in each pile.

Question 5.

Nate solves the equation _____ Ã— 5 = 15 by writing and solving 15 Ã· 5 = ____. Explain why Nateâ€™s method works.

Answer:

Nate solves the equation as 3 Ã— 5 = 15,

Explanation:

Given Nate solves the equation _____ Ã— 5 = 15 by writing and solving as 15 Ã· 5 = 3, Nate’s method is correct because in the given equation ___ X 5 = 15 , we bring 5 to the other side it becomes as

15 Ã· 5 = 3 now we check as 3 Ã— 5 it becomes 15 only.

So Nate’s method work.

Question 6.

The blanks in Problem 5 represent the number of groups.

Draw an array to represent the equations.

Explanation:

Drawn an array to represent the equations as

3 Ã— 5 = 15 or 15 Ã· 5 = 3 as shown in the picture above.