Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key

Practicing the Bridges in Mathematics Grade 4 Student Book Answer Key Unit 4 Module 1 will help students analyze their level of preparation.

Bridges in Mathematics Grade 4 Student Book Answer Key Unit 4 Module 1

Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Session 1 Answer Key

Work Place Instructions 4A Target One Thousand

Each pair of players needs:

  • a deck of Number Cards to share
  • a Target One Thousand Record Sheet for each player

1. One player removes the wild cards from the deck, shuffles the remaining cards well, and deals out 8 cards to each player.
2. Players choose 6 of their 8 cards to make two 3-digit numbers. Players try to form numbers that will total as close to 1,000 as possible, either under or over.
(Example: If a player used the cards 1, 2, 4, 5, 6, and 8, she could make 156 + 824 = 980 or she could make 156 + 842 = 998. She would choose 156 + 842 because 998 is closer to 1,000 than 980.)
3. Players find the sums of their numbers.
4. Players double-check each other’s addition. When players agree on the sums, each player writes an addition equation for the chosen numbers on his record sheet.
5. Players figure out their scores by finding the differences between their sums and 1,000.
(Examples: A sum of 980 has a score of 20. A sum of 1,002 has a score of 2. A sum of 1,000 has a score of 0.)
6. Players record both players’ scores on their record sheets and put their used cards face up in a discard stack.
7. Then the dealer hands out 6 new cards to each player so they both have 8 cards again.
8. After three rounds, players add their three scores to determine the winner. The player with the lower total wins the game.

Game Variations

A. After players have mastered the original instructions, they can include the wild cards. A wild card can be any digit. If a player uses a wild card, he should put a star above the number made from the wild card in the equation on the record sheet.
B. Use a different target sum, and a different number of cards. If players decide to play for 10,000, they would each get 10 cards, and use 8 of them to make two 4-digit numbers that will total as close to 10,000 as possible.

Mixed Review

Question 1.
Sketch and label a picture that represents 2\(\frac{3}{4}\).
Answer:
\(\frac{11}{4}\) or 2\(\frac{3}{4}\),

Explanation:
Sketched and labeled a picture that represents 2\(\frac{3}{4}\) as it is in mixed fraction we write in fraction also as \(\frac{2 X 4 + 3}{4}\) = \(\frac{11}{4}\) above.

Question 2.
Write each fraction as a mixed number. Make a drawing, if needed.

a. \(\frac{5}{2}\) = _____
Answer:
2\(\frac{1}{2}\),

Explanation:
Asked to write in mixed fraction \(\frac{5}{2}\) as numerator is greater we write as \(\frac{2 X 2 + 1}{2}\) = 2\(\frac{1}{2}\).

b. \(\frac{7}{6}\) = _____
Answer:
1\(\frac{1}{6}\),

Explanation:
Asked to write in mixed fraction \(\frac{7}{6}\) as numerator is greater we write as \(\frac{1 X 6 + 1}{6}\) = 1\(\frac{1}{6}\).

c. \(\frac{4}{3}\) = _____
Answer:
1\(\frac{1}{3}\),

Explanation:
Asked to write in mixed fraction \(\frac{4}{3}\) as numerator is greater we write as \(\frac{1 X 3 + 1}{3}\) = 1\(\frac{1}{3}\).

d. \(\frac{12}{8}\) = _____
Answer:
\(\frac{3}{2}\) or 1\(\frac{1}{2}\),

Explanation:
Asked to write in mixed fraction \(\frac{12}{8}\) as both numerator and denominator goes by 4 we get \(\frac{4 X 3}{4 X 2}\) = \(\frac{3}{2}\) as numerator is greater we write as \(\frac{1 X 2 + 1}{2}\) = 1\(\frac{1}{6}\).

Question 3.
Fill in the table to show each value as money, a decimal, or a fraction.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 22
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-2

Explanation:
Filled in the table to show each value as money, a decimal, or a fraction above.

Question 4.
Add these pairs of fractions. Express the answer for each as a fraction with denominator 100.
\(\frac{3}{10}\) + \(\frac{45}{100}\) =
\(\frac{7}{10}\) + \(\frac{63}{100}\) =
\(\frac{1}{10}\) + \(\frac{39}{100}\) =
\(\frac{4}{10}\) + \(\frac{23}{100}\) =
Answer:
\(\frac{75}{100}\),
\(\frac{133}{100}\) or 1\(\frac{33}{100}\),
\(\frac{49}{100}\),
\(\frac{63}{100}\),

Explanation:
Adding the pairs of fractions
\(\frac{3}{10}\) + \(\frac{45}{100}\) we make common denominator as
\(\frac{3 X 10}{10 X 10}\) + \(\frac{45}{100}\) = \(\frac{30}{100}\) + \(\frac{45}{100}\) now we can add numerators as \(\frac{30 + 45}{100}\)  = \(\frac{75}{100}\),
Now \(\frac{7}{10}\) + \(\frac{63}{100}\) we make common denominator as \(\frac{7 X 10}{10 X 10}\) + \(\frac{63}{100}\) = \(\frac{70}{100}\) + \(\frac{63}{100}\) now we can add numerators as \(\frac{70 + 63}{100}\)  = \(\frac{133}{100}\) as numerator is greater than denominator we write in mixed fraction as \(\frac{1 X 100 + 33}{100}\) = 1\(\frac{33}{100}\).
Now \(\frac{1}{10}\) + \(\frac{39}{100}\) we make common denominator as \(\frac{1 X 10}{10 X 10}\) + \(\frac{39}{100}\) = \(\frac{10}{100}\) + \(\frac{39}{100}\) now we can add numerators as \(\frac{10 + 39}{100}\)  = \(\frac{49}{100}\),
\(\frac{4}{10}\) + \(\frac{23}{100}\) we make common denominator as \(\frac{4 X 10}{10 X 10}\) + \(\frac{23}{100}\) = \(\frac{40}{100}\) + \(\frac{23}{100}\) now we can add numerators as \(\frac{40 + 23}{100}\)  = \(\frac{63}{100}\).

Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Session 2 Answer Key

Round ‘Em Up!

Question 1.
Solve the problems below. Show all your work.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 1
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-3

Explanation:
Solved the given problems as shown above.

Question 2.
Round the numbers below to the nearest ten. When you round to the nearest ten, look at the number in the ones place. If it is 5 or higher, round up to the next highest ten. If it is less than 5, keep the number in the tens place the same.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 2
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-4

Explanation:
Rounded the numbers below to the nearest ten as a. 47 to 50, b. 52 to 50, c. 35 to 40, d. 94 to 90, e. 122 to 120, f. 856 to 860 g. 267 to 270 h. 993 to 990 i. 1,247 to 1,250, j. 2,052 to 2,050.

Question 3.
Round the numbers below to the nearest hundred. When you round to the nearest hundred, look at the number in the tens place. If it is 5 or higher, round up to the next highest hundred. If it is less than 5, keep the number in the hundreds place the same.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 3
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-5

Explanation:
Rounded the numbers below to the nearest hundred. When I round to the nearest hundred, looked at the number in the tens place. If it is 5 or higher, round up to the next highest hundred. If it is less than 5, keep the number in the hundreds place the same as a. 203 to 200,
b. 254 to 300, c. 822 to 800, d. 439 to 400, e. 67 to 100, f. 153 to 200, g. 764 to 800, h. 449 to 400 and i. 657 to 700.

Question 4.
CHALLENGE Write two different numbers that round up or down to each number shown.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 4
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-6

Explanation:
Wrote two different numbers that round up or down to each number shown above as for a. 20 up 42 down 8  b. 80 up 96 down 53 c. 100 up 124 down 74 d. for 300 up 305 down 294 and e. 700 up 721 and down 689 written above.

Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Session 3 Answer Key

The Dodgers & The Yankees

20,137,408 people went to see the Los Angeles Dodgers play baseball between 2001 and 2006. That’s twenty million, one hundred thirty-seven thousand, four hundred eight baseball fans!

Question 1.
Here’s a chart that shows the place value of every digit in the number 20,137,408.
Use the information on the chart to answer questions a-i below.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 5

a. The digit in the millions place is: _____

b. The digit in the ten thousands place is: ______

c. The digit in the hundred thousands place is: _____

d. The digit in the ten millions place is: _____

e. Are there any hundred millions in this number? _____

f. The digit in the hundreds place is: _____

g. The digit in the thousands places is: _____

h. The digit in the ones place is: _____

i. The digit in the tens place is: ____

Answer:
a. The digit in the millions place is: Zero-0,
b. The digit in the ten thousands place is: Three- 3,
c. The digit in the hundred thousands place is: One-1,
d. The digit in the ten millions place is:Two-2,
e. Are there any hundred millions in this number? No,
f. The digit in the hundreds place is: Four-4,
g. The digit in the thousands places is: Seven-7,
h. The digit in the ones place is: Eight-8,
i. The digit in the tens place is: Zero-0,

Explanation:
Used the chart that showed the place value of every digit in the number 20,137,408 above
Used the information of the chart to answer questions a-i above.

Rounding to the Nearest Thousand

Question 1.
What is 6,780 rounded to the nearest thousand? Fill in the bubble to show.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 5,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 6,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 7,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 8,000
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-7

Explanation:
6,780 rounded to the nearest thousand is 7,000 filled in the bubble to show it.

Question 2.
What is 5,438 rounded to the nearest thousand? Fill in the bubble to show.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 5,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 6,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 7,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 8,000
Answer:

Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-8

Explanation:
5,438 rounded to the nearest thousand as 5,000 filled in the bubble to show it.

Question 3.
It is 4,991 kilometers from Vancouver, BC, to Montreal. What is 4,991 rounded to the nearest thousand?
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 5,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 6,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 41,000
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 49,000
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-9

Explanation:
Given it is 4,991 kilometers from Vancouver, BC, to Montreal. So 4,991 rounded to the nearest thousand 5,000 filled the bubble above.

Question 4.
People in Canada measure long distances in kilometers instead of miles. Tera and her family drove from Tucker to Dry Creek last weekend. About how many kilometers did they drive? Fill in the bubble to show the best estimate.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 7
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 1,050 kilometers
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 1,100 kilometers
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 6 1,150 kilometers
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-10

Explanation:
Given people in Canada measure long distances in kilometers instead of miles. Tera and her family drove from Tucker to Dry Creek last weekend. So many kilometers did they drive is  674 km + 468 km = 1,142 km nearest is 1,100 filled in the bubble to show the best estimate above.

Question 5.
It is 1,164 kilometers from Vancouver, BC, to Edmonton. What is 1,164 rounded to the nearest thousand? Fill in the answer below.

1,164 kilometers rounded to the nearest thousand is _____
Answer:
1,164 kilometers rounded to the nearest thousand is 1,000,

Explanation:
As it is 1,164 kilometers from Vancouver, BC, to Edmonton. So is 1,164 rounded to the nearest thousand is 1,000.

Question 6.
It is 2,668 kilometers from Winnipeg to Kitimat. What is 2,668 rounded to the nearest thousand? Fill in the answer below.

2,668 kilometers rounded to the nearest thousand is _____
Answer:
2,668 kilometers rounded to the nearest thousand is 3,000,

Explanation:
Given it is 2,668 kilometers from Winnipeg to Kitimat.  2,668 rounded to the nearest thousand is 3,000.

Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Session 4 Answer Key

Work Place Instructions 4B Add, Round & Compare

Each pair of players needs:

  • a 4B Add, Round & Compare Record Sheet to share
  • a deck of Number Cards

1. Players work together to remove the wild cards and the 10s from the deck of cards, shuffle them thoroughly, and place the deck face-down between them. Each player draws a card from the stack; the player with the greater number goes first.
2. Player 1 draws 3 cards from the deck, places them in any order he chooses to form a 3-digit number, and then writes that number on the record sheet. Then he rearranges the same 3 cards to form a different 3-digit number, and writes that on the sheet as well.
3. Player 1 rounds each number to the nearest hundred and writes the rounded numbers in the first row of the Rounded Numbers column of the record sheet.
4. Player 1 adds the actual numbers and the rounded numbers and records each sum on the record sheet Player 2 checks Player 1’s addition.
5. Player 1 finds the difference between the rounded numbers and the actual numbers and records it in the last column on the record sheet.
Sometimes the actual number will be larger, and sometimes the rounded number will be larger. Players write the larger number in the first line of the equation.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 8
Riley I got a 5, a 2, and a 4. I decided to use those numbers to make 542for the first number and 254 for the second number. I didn’t know it would turn out so well, but maybe it’s good if you make one number that rounds down and one that rounds up. So my rounded numbers were 500 and 300, which is 800, and the difference between my actual total and the rounded total was only 4!
6. Now it is Player 2’s turn. Player 2 repeats steps 2-5.
7. After three rounds of the game, players add their scores from all three rounds. The player with the lower score wins the game.

Game Variations

A. Players can play Add, Round & Compare with 2-digit numbers by drawing only 2 cards instead of 3 on each turn, and rounding to the nearest 10 instead of the nearest 100.
B. Players can roll a more/less die before they start to play or at the very end of the game. If the die says more, the player with the higher score wins. If the die says /ess, the player with the lower score wins.
C. Players can play the game with 4-digit numbers by drawing 4 cards instead of 3 on each turn, and rounding to the nearest 1,000 instead of the nearest 100.

Adding Larger Numbers

Question 1.
Solve each problem below. Show your work.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 9
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-11

Explanation:
Solved the given each problem above.

Question 2.
Keiko has to add 3,996 and 4,204. What is an easy way for Keiko to add these two numbers? Solve the problem and show your work.
Answer:
8,200,

Explanation:
Given Keiko has to add 3,996 and 4,204.  An easy way for Keiko to add these two numbers is adding accordingly to their place values as
111
3,996
4,204
8,200.

Question 3.
Max is playing Add, Round & Compare with a partner. He got a 3, an 8, and a 4 on his first turn. He decided to use those numbers to make 348 and 843.
a. What are his rounded numbers? ____ and _____
Answer:
300 and 800,

Explanation:
As Max is playing Add, Round & Compare with a partner. He got a 3, an 8, and a 4 on his first turn. He decided to use those numbers to make 348 and 843. So his rounded numbers are 300 and 800.

b. What is the sum of his rounded numbers? _____
Answer:
1,100,

Explanation:
The sum of his rounded numbers is 300 + 800 = 1,100.

c. What is the sum of his actual numbers? Show your work.
Answer:
1,191,

Explanation:
The sum of his actual numbers are 348 and 843 is
1
348
+843
1,191.

d. What is the difference between the sum of his rounded numbers and the sum of his actual numbers? Show your work.
Answer:
Difference of sum of his rounded numbers and the sum of his actual numbers is 91,

Explanation:
The difference between the sum of his rounded numbers and the sum of his actual numbers is 1,191 – 1,100 =
1,191
-1,100
91.

e. CHALLENGE Think of a way to arrange the three numbers Max got (3, 8, and 4) so there’s less difference between his actual and rounded scores. Show your work.
Answer:
384,

Explanation:
Asked to think of a way to arrange the three numbers Max got (3, 8, and 4) so there’s less difference between his actual and rounded scores if we take 384 the rounded score is 400 and difference is 400 – 384 = 16, next 348 rounded 300 difference is 348 – 300 = 48,
next 834 rounded to 800 difference is 834 – 8 =34, if 843 rounded to 800 only difference is 843 – 800 = 43, Now 438 rounded to 400 difference is 438 – 400 = 38, if 483 then rounded to 500 difference is 500 – 483 = 17 so the best one is 384.

Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Session 5 Answer Key

Addition Practice

Question 1.
Solve the addition problems below using any strategy that works well for you.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 10
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-13
Strategy:
Standard algorithm,

Explanation:
Solved the addition problem above using strategy of Standard algorithm.

Question 2.
Solve the addition problems below using the standard algorithm.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 11
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-14

Explanation:
Solved the addition problems above using the standard algorithm.

Question 3.
Write this number in words: 627,391.
Answer:
Six lakhs twenty seven thousand three hundred and ninety one,

Explanation:
Asked to write the given number : 627,391 in words so it is Six lakhs twenty seven thousand three hundred and ninety one.

Question 4.
Write two hundred fifty-three thousand, eight hundred eighteen in numbers.
Answer:
2,53,818,

Explanation:
Asked to write two hundred fifty-three thousand, eight hundred eighteen in numbers so it is
2,53,818.

Question 5.
Write this number in expanded form: 56,789.
ex 32,569 = 30,000 + 2,000 + 500 + 60 + 9
Answer:
50,000 + 6,000 + 700 + 80 + 9,

Explanation:
Asked to write this number in expanded form: 56,789 is 50,000 + 6,000 + 700 + 80 + 9.

Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Session 6 Answer Key

Question 1.
Show your thinking and the answer for problems a and b below.

a. If the telephone was invented in 1876, when was it 98 years old?
Answer:
1974,

Explanation:
If the telephone was invented in 1876, when was it 98 years old is 1876 + 98 = 1974.

b. If the hot air balloon was invented in 1783, when was it 197 years old?
Answer:
1980,

Explanation:
If the hot air balloon was invented in 1783, when was it 197 years old is 1783 + 197 = 1980.

Question 2.
Fill in the blanks correctly.
57 + 99 = ____ + 100 , 199 + 357 = ___ + 356, 1,999 + 481 = ___ + 480
Answer:
57 + 99 = 56 + 100, 199 + 357 = 200 + 356, 1,999 + 481 = 2,000 + 480,

Explanation:
Fill in the blanks as left side it is 57 + 99 = 156 so right side 156 – 100 = 56, 199 + 357  = 556,
so it is 556 – 200 = 336, Now 1,999 + 481 = 2,480 right side it is 2,480 – 480 = 2,000 therefore it is 57 + 99 = 56 + 100, 199 + 357 = 200 + 356, 1,999 + 481 = 2,000 + 480.

Question 3.
Solve each addition combination below using the standard algorithm. Then check to make sure your answer is reasonable by rounding each addend to the nearest hundred, finding the total, and comparing it to the answer you got for the actual numbers.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 12
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-15

Explanation:
Solved each addition combination above using the standard algorithm. Then checked to make sure my answer is reasonable by rounding each addend to the nearest hundred, finding the total, and comparing it to the answer I got for the actual numbers.

Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Session 7 Answer Key

Show your thinking and the answer.

Question 1.
The Music Academy was founded in 1847.

a. In what year was the academy 95 years old?
Answer:
In the year 1942,

Explanation:
Given the Music Academy was founded in 1847 in the year was the academy 95 years old is 1847 + 95 = 1942.

b. In what year was the academy 150 years old?
Answer:
In the year 1997,

Explanation:
Given the Music Academy was founded in 1847 in the year was the academy 150 years old is 1847 + 150 = 1997.

c. In what year will the academy be 275 years old?
Answer:
In the Year 2122,

Explanation:
Given the Music Academy was founded in 1847 in the year was the academy 275 years old is 1847 + 275 = 2122.

Question 2.
Fill in the blanks.
76 + 85 = 75 + ___ 298 + ___ = 300 + 127 725 + 174 = ___ + 199
Answer:
76 + 85 = 75 + 86, 298 + 129 = 300 + 127, 725 + 174 = 700 + 199,

Explanation:
Asked to fill the blanks as left side it is 76 + 85 = 161 right side is 161 – 75 = 86, right side it is 300 + 127 = 427, left side it is 427 – 298 = 129, left side it is 725 + 174 = 899 so right side is 899 – 199 = 700. So it is 76 + 85 = 75 + 86, 298 + 129 = 300 + 127, 725 + 174 = 700 + 199.

Question 3.
Fill in the ratio table below.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 13
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-16

Explanation:
Filled in the ration as 1 package = 16 Tortillas, 2 will have 2 X 16 = 32, 64 Tortillas means 64 /16  = 4 packages, 8 means 8 X 16 = 128, 144 Tortillas means 144/16 = 9 packages, 10 packages means 10 X 16 = 160 Tortillas filled in the ratio table above.

Question 4.
The top part of the ratio table below is missing. Fill in the blanks in the mystery ratio table below.
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key 14
Answer:
Bridges in Mathematics Grade 4 Student Book Unit 4 Module 1 Answer Key-17
Explanation:
Let x be the value 11 times x is equal to 143 so x = 143/11 = 13 so missing ratios are for 130 it is 130/13 = 10, for 13 it is 13 X 13 = 169, for 182 it is 182/13 = 14 and for 15 it is 15 X 13 = 195 so filled in the blanks above.

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