The solutions to Bridges in Mathematics Grade 3 Student Book Answer Key Unit 7 Module 2 can help students to clear their doubts quickly.
Bridges in Mathematics Grade 3 Student Book Answer Key Unit 7 Module 2
Bridges in Mathematics Grade 3 Student Book Unit 7 Module 2 Session 1 Answer Key
Sandwiches, Pizza & Books
Question 1.
Rodney had a friend over on Saturday. His dad took them out for sandwiches. Each person (Rodney, his dad, and his friend) got a sandwich for $6. How much did they spend on sandwiches in all? Show all your work.
Answer:
Amount of money they spend on sandwiches in all = $18.
Explanation:
Number of persons = 3.
Cost of sandwich they got = $6.
Amount of money they spend on sandwiches in all = Number of persons × Cost of sandwich they got
= 3 × $6
= $18.
Question 2.
Jasmine had a pizza party with 3 of her friends to celebrate the last day of school. They ordered 2 pizzas. Each pizza had 8 slices. They all ate the same amount of pizza and finished both pizzas. How many pieces did each person eat? Show all your work.
Answer:
Number of pieces each person ate = 4.
Explanation:
Number of persons attended to celebrate the last day of school = 4.
Number of pizzas they ordered = 2.
Number of slices each pizza has = 8.
Number of pieces each person ate = (Number of pizzas they ordered × Number of slices each pizza has) ÷ Number of persons attended to celebrate the last day of school
= (2 × 8) ÷ 4
= 16 ÷ 4
= 4.
Question 3.
CHALLENGE There were 12,387 books in the school library. The librarian bought 445 more books to add to the library and put 126 books on the Give Away shelf near the office. How many books are in the library now? Show all your work.
Answer:
Number of books are in the library now = 12,706.
Explanation:
Number of books in the school librarythere were = 12,387.
Number of more books the librarian bought to add to the library = 445.
Number of books she puts on the Give Away shelf near the office = 126.
Number of books are in the library now = (Number of books in the school librarythere were + Number of more books the librarian bought to add to the library) – Number of books she puts on the Give Away shelf near the office
= (12,387 + 445) – 126
= 12,832 – 126
= 12,706.
Bridges in Mathematics Grade 3 Student Book Unit 7 Module 2 Session 2 Answer Key
Multiplication Practice
Question 1.
Solve these problems in your head. Write the answers.
Answer:
Explanation:
Given Equations missing results:
8 × 3 = 24.
9 × 3 = 27.
10 × 3 = 30.
20 × 3 = 60.
40 × 3 = 120.
50 × 3 = 150.
60 × 3 = 180.
70 × 3 = 210.
80 × 3 = 240.
90 × 3 = 270.
100 × 3 = 300.
1,000 × 3 = 3,000.
Question 2.
Explain how you figured out the answers to the problems above.
Answer:
I have figured out all answers by doing multiplication.
Explanation:
Question 3.
Solve these problems in your head. Write the answers.
Answer:
Explanation:
Given Equations missing results:
10 × 4 = 40.
20 × 5 = 100.
30 × 7 = 210.
40 × 2 = 80.
50 × 5 = 250.
60 × 4 = 240.
700 × 5 = 3,500.
80 × 4 = 320.
90 × 5 = 450.
20 × 8 = 160.
30 × 9 = 270.
60 × 8 = 480.
70 × 2 = 140.
80 × 5 = 400.
40 × 4 = 160.
30 × 6 = 180.
60 × 5 = 300.
20 × 9 = 180.
30 × 8 = 240.
70 × 4 = 280.
90 × 5 = 450.
Challenge:
900 × 9 = 8,100.
400 × 8 = 3,200.
800 × 9 = 7,200.
600 × 10 = 6,000.
700 × 11 = 7,700.
800 × 8 = 6,400.
800 × 11 = 8,800.
Bridges in Mathematics Grade 3 Student Book Unit 7 Module 2 Session 3 Answer Key
Working with Equations
Question 1.
Fill in the missing numbers to make each equation true.
35 ÷ 7 = 20 ÷ ________
8 × 3 = 40 – ____________
8 × ____________ = 36 + 28
0 × 67 = __________ × 45
19 + ___________ = 9 × 5
9 × ___________ = 668 – 587
3 × 9 = 68 – ____________
42 ÷ 6 = 63 – _____________
Answer:
Equations:
35 ÷ 7 = 20 ÷ 4.
8 × 3 = 40 – 16.
8 × 8 = 36 + 28.
0 × 67 = 0 × 45.
19 + 26 = 9 × 5.
9 × 9 = 668 – 587.
3 × 9 = 68 – 41.
42 ÷ 6 = 63 – 56.
Explanation:
Missing numbers :
35 ÷ 7 = 20 ÷ ??
=> 5 = 20 ÷ ??
=> ?? = 20 ÷ 5
=> ?? = 4.
8 × 3 = 40 – ??.
=> 24 = 40 – ??
=> ?? = 40 – 24
=> ?? = 16.
8 × ?? = 36 + 28.
=> 8 × ?? = 64.
=> ?? = 64 ÷ 8
=> ?? = 8.
0 × 67 = ?? × 45.
=> 0 = ?? × 45
=> 0 ÷ 45 = ??
=> 0 = ??.
19 + ?? = 9 × 5.
=> 19 + ?? = 45.
=> ?? = 45 – 19
=> ?? = 26.
9 × ?? = 668 – 587.
=> 9 × ?? = 81
=> ?? = 81 ÷ 9
=> ?? = 9.
3 × 9 = 68 – ?? .
=> 27 = 68 – ??
=> ?? = 68 – 27
=> ?? = 41.
42 ÷ 6 = 63 – ??.
=> 7 = 63 – ??
=> ?? = 63 – 7
=> ?? = 56.
Question 2.
Use <, >, or = to complete each equation.
54 ÷ 6 < 54 ÷ 2
32 × 10 __________ 13 × 100
125 + 230 ___________ 100 + 255
144 ÷ 12 ____________ 144 ÷ 6
197 + 326 ___________ 284 + 139
300 – 250 ___________ 350 – 300
Answer:
Equations:
54 ÷ 6 < 54 ÷ 2.
32 × 10 < 13 × 100.
125 + 230 = 100 + 255.
144 ÷ 12 < 144 ÷ 6.
197 + 326 > 284 + 139.
300 – 250 = 350 – 300.
Explanation:
Given Equations:
54 ÷ 6 < 54 ÷ 2.
32 × 10 = 320. 13 × 100 = 1300.
=> 32 × 10 is lesser than 13 × 100.
125 + 230 = 355. 100 + 255 = 355.
=> 125 + 230 is equal to 100 + 255.
144 ÷ 12 = 12. 144 ÷ 6 = 24.
=> 144 ÷ 12 is lesser than 144 ÷ 6.
197 + 326 = 523. 284 + 139 = 423.
=> 197 + 326 is greater than 284 + 139.
300 – 250 = 50. 350 – 300 = 50.
=> 300 – 250 is equal to 350 – 300.
Question 3.
CHALLENGE Fill in the missing number to make each equation true.
(20 × __________) ÷ 4 = 25
(36 ÷ 4) × __________ = 81
350 = (___________ × 50) – 50
1,826 = (10 × __________) – 100 – 74
(245 + __________) × 3 = 900
(1,008 – 508) ÷ ___________ = 5
Answer:
Given Equations:
(20 × 4 ) ÷ 4 = 25.
(36 ÷ 4) × 9 = 81.
350 = (8 × 50) – 50.
1,826 = (10 × 200 ) – 100 – 74.
(245 + 55 ) × 3 = 900.
(1,008 – 508) ÷ 100 = 5.
Explanation:
Missing numbers in Equations:
(20 × ?? ) ÷ 4 = 25.
=> (20 × ?? ) = 25 × 4
=> (20 × ?? ) = 100.
=> ?? = 100 ÷ 4
(36 ÷ 4) × ?? = 81.
=> ?? = (81 × 4) ÷ 36
=> ?? = 324 ÷ 36
=> ?? = 9.
350 = (?? × 50) – 50.
=> 350 + 50 = (?? × 50)
=> 400 = (?? × 50)
=> 400 ÷ 50 = ??
=> 8 = ??.
1,826 = (10 × ?? ) – 100 – 74.
=> 1826 + 74 = (10 × ?? ) – 100
=> 1900 + 100 = (10 × ?? )
=> 2000 = (10 × ?? )
=> 2000 ÷ 10 = ??
=> 200 = ??.
(245 + ?? ) × 3 = 900.
=> (245 + ?? ) = 900 ÷ 3
=> (245 + ?? ) = 300
=> ?? = 300 – 245
=> ?? = 55.
(1,008 – 508) ÷ ?? = 5.
=> 500 ÷ ?? = 5.
=> 500 ÷ 5 = ??
=> 100 = ??.
Question 4.
CHALLENGE Use <, >, or = to complete each equation.
(25 × 4) ÷ 10 ___________ 81 ÷ 9
(514 – 489) × 6 ___________ 50 × 3
(75 × 2) – 51 ___________ (100 ÷ 2) × 4
(328 + 22) – 150 ___________ 500 ÷ 2
(739 + 261) ÷ 10 ___________ 20 × 5
5 × 5 × 5 ___________ (200 ÷ 2) + 50
Answer:
Given Equations:
(25 × 4) ÷ 10 > 81 ÷ 9.
(514 – 489) × 6 = 50 × 3.
(75 × 2) – 51 < (100 ÷ 2) × 4.
(328 + 22) – 150 < 500 ÷ 2.
(739 + 261) ÷ 10 = 20 × 5.
5 × 5 × 5 < (200 ÷ 2) + 50.
Explanation:
Given Equations:
(25 × 4) ÷ 10 = 100 ÷ 10 = 10. 81 ÷ 9 = 9.
=> (25 × 4) ÷ 10 is greater than 81 ÷ 9.
(514 – 489) × 6 = 25 × 6 = 150. 50 × 3 = 150.
=> (514 – 489) × 6 is equal to 50 × 3.
(75 × 2) – 51 = 150 – 51 =99. (100 ÷ 2) × 4 = 50 × 4 = 200.
=> (75 × 2) – 51 is lesser than (100 ÷ 2) × 4.
(328 + 22) – 150 = 350 – 150 = 200. 500 ÷ 2 = 250.
=> (328 + 22) – 150 is lesser than 500 ÷ 2.
(739 + 261) ÷ 10 = 1000 ÷ 10 = 100. 20 × 5 = 100.
=> (739 + 261) ÷ 10 is equal to 20 × 5.
5 × 5 × 5 = 25 × 5 = 125. (200 ÷ 2) + 50 = 100 + 50 = 150.
=> 5 × 5 × 5 is lesser than (200 ÷ 2) + 50.
Bridges in Mathematics Grade 3 Student Book Unit 7 Module 2 Session 4 Answer Key
Multiplication Review
Question 1.
Complete the multiplication facts.
Answer:
Explanation:
GIven missing Equations:
10 × 6 = 60.
30 × 2 = 60.
50 × 8 = 400.
90 × 3 = 270.
40 × 7 = 280.
50 × 3 = 150.
60 × 4 = 240.
Question 2.
Fill in the missing number to complete each multiplication equation. Then write a related division equation.
4 × 5 = 20 20 ÷ 5 = 4
__________ × 2 = 16 __________÷ ________ = ___________
5 × __________ = 35 __________÷ ________ = ___________
_________ × 9 = 18 __________÷ ________ = ___________
Answer:
4 × 5 = 20 20 ÷ 5 = 4
8 × 2 = 16. 16 ÷ 8 = 2.
5 × 7 = 35. 35 ÷ 7 = 5.
2 × 9 = 18. 18 ÷ 2 = 9.
Explanation:
Given Missing numbers:
4 × 5 = 20 20 ÷ 5 = 4
?? × 2 = 16
=> ?? = 16 ÷ 2
=> ?? = 8. ______16_____ ÷ ____8________ = ____2________.
5 × ?? = 35.
=> ?? = 35 ÷ 5
=> ?? = 7. ____35_______ ÷ _____7_______ = _____5_______.
?? × 9 = 18.
=> ?? = 18 ÷ 9
=> ?? = 2. ____18_______ ÷ ______2______ = _____9_______.
Question 3.
Jenny made 3 bracelets with 8 beads each. Then she made 4 bracelets with 9 beads each. How many beads did she use in all?
a. Write an equation to represent this problem. Use a letter to stand for the unknown quantity.
Answer:
Total number of beads she used in all =60.
Explanation:
Number of bracelets Jenny made = 3.
Number of beads each bracelets made up = 8.
Number of bracelets Jenny made = 4.
Number of beads each bracelets made up = 9.
Total number of beads she used in all = (Number of bracelets Jenny made × Number of beads each bracelets made up) + (Number of bracelets Jenny made × Number of beads each bracelets made up)
= (3 × 8) + (4 × 9)
= 24 + 36
= 60.
b. Solve the problem. Show all your work.
Answer:
Total number of beads she used in all = (3 × 8) + (4 × 9) = 24 + 36 = 60.
Explanation:
Number of bracelets Jenny made = 3.
Number of beads each bracelets made up = 8.
Number of bracelets Jenny made = 4.
Number of beads each bracelets made up = 9.
Total number of beads she used in all = (Number of bracelets Jenny made × Number of beads each bracelets made up) + (Number of bracelets Jenny made × Number of beads each bracelets made up)
= (3 × 8) + (4 × 9)
= 24 + 36
= 60.
Question 4.
CHALLENGE Solve the following:
Answer:
Explanation:
Given Equations:
21 × 10 = 210.
21 × 5 = 105.
43 × 2 = 86.
62 × 10 = 620.
62 × 5 = 310.
26 × 3 = 78.
382 × 2 = 764.
Bridges in Mathematics Grade 3 Student Book Unit 7 Module 2 Session 5 Answer Key
Multiplication Equations
Question 1.
Multiply.
Answer:
Explanation:
Given Equations:
20 × 6 = 120.
40 × 5 = 200.
30 × 7 = 210.
9 × 20 = 180.
8 × 40 = 320.
30 × 3 = 90.
90 × 2 = 180.
Question 2.
Circle T or F to show whether the equations below are true or false.
ex: 4 × 5 = 5 × 4
a. 3 × 20 = 3 × 2 × 10
T
F
Answer:
3 × 20 = 3 × 2 × 10 is True.
Explanation:
Given Equation:
3 × 20 = 60.
3 × 2 × 10 = 6 × 10 = 60.
b. 6 × 30 = 6 × 3 × 30
T
F
Answer:
6 × 30 = 6 × 3 × 30 is False.
Explanation:
Given Equation:
6 × 30 = 180.
6 × 3 × 30 = 18 × 30 = 540.
c. (2 × 5) × 4 = 2 × (5 × 4)
T
F
Answer:
(2 × 5) × 4 = 2 × (5 × 4) is True.
Explanation:
Given Equation:
(2 × 5) × 4 = 10 × 4 = 40.
2 × (5 × 4) = 2 × 20 = 40.
d. (2 × 4) × 6 = 2 + (4 × 6)
T
F
Answer:
(2 × 4) × 6 = 2 + (4 × 6) is False.
Explanation:
Given Equation:
(2 × 4) × 6 = 8 × 6 = 48.
2 + (4 × 6) = 2 + 24 = 26.
Question 3.
Solve each pair of equations, and circle the one that seemed easier to solve.
a. (2 × 5) × 8 = ______________ 2 × (5 × 8) = ______________
Answer:
(2 × 5) × 8 = 80. 2 × (5 × 8) = 80.
Explanation:
Given Equations:
(2 × 5) × 8 = 10 × 8 = 80.
2 × (5 × 8) = 2 × 40 = 80.
=> (2 × 5) × 8 = 10 × 8 = 80 is easier than 2 × (5 × 8) = 2 × 40 = 80.
b. (5 × 2) × 4 = ______________ 5 × (2 × 4) = ______________
Answer:
(5 × 2) × 4 = 40. 5 × (2 × 4) = 40.
Explanation:
Given Equations:
(5 × 2) × 4 = 10 × 4 = 40.
5 × (2 × 4) = 5 × 8 = 40.
=> (5 × 2) × 4 = 10 × 4 = 40 is easier than 5 × (2 × 4) = 5 × 8 = 40.
c. (5 × 4) × 3 = ______________ 5 × (4 × 3) = ______________
Answer:
(5 × 4) × 3 = 60. 5 × (4 × 3) = 60.
Explanation:
Given Equations:
(5 × 4) × 3 = 20 × 3 = 60.
5 × (4 × 3) = 5 × 12 = 60.
=> (5 × 4) × 3 = 20 × 3 = 60 is easier than 5 × (4 × 3) = 5 × 12 = 60.
d. (10 × 3) × 5 = ______________ 10 × (3 × 5) = ______________
Answer:
(10 × 3) × 5 = 150. 10 × (3 × 5) = 150.
Explanation:
Given Equations:
(10 × 3) × 5 = 30 × 5 = 150.
10 × (3 × 5) = 10 × 15 = 150.
=> 10 × (3 × 5) = 10 × 15 = 150 is easier than (10 × 3) × 5 = 30 × 5 = 150.
Question 4.
Rob says 4 × 14 is the same as (4 × 10) + (4 × 4). Is he right? Explain why or why not.
Answer:
Yes, Rob says 4 × 14 is the same as (4 × 10) + (4 × 4) is correct because they both are having same result.
Explanation:
Rob says 4 × 14 is the same as (4 × 10) + (4 × 4).
Equations:
=> 4 × 14 = 56.
(4 × 10) + (4 × 4) = 40 + 16 = 56.
Both Equations are same.
Question 5.
Solve each equation below. Show all of your work.
(5 × 10) + (5 × 3) = ______________
(6 × 20) + (6 × 2) = ______________
(3 × 50) + (3 × 2) = ______________
Answer:
Equations:
(5 × 10) + (5 × 3) = 55.
(6 × 20) + (6 × 2) = 132.
(3 × 50) + (3 × 2) = 156.
Explanation:
Given Equations:
(5 × 10) + (5 × 3) = 50 + 15 = 55.
(6 × 20) + (6 × 2) = 120 + 12 = 132.
(3 × 50) + (3 × 2) = 150 + 6 = 156.