Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key

The solutions to Bridges in Mathematics Grade 3 Home Connections Answer Key Unit 3 Module 1 can help students to clear their doubts quickly.

Bridges in Mathematics Grade 3 Home Connections Answer Key Unit 3 Module 1

Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Session 1 Answer Key

Multiplying & Dividing

Question 1.
Complete the multiplication facts.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 1
Answer:
Multiplication:
Bridges-in-Mathematics-Grade-3-Home-Connections-Answer-Key-Unit-3-Module-1-Multiplying & Dividing-1

Explanation:
Given Equations: Multiplication:
5 × 6 = 30.     2 × 7 = 14.      1 × 2 = 2.       5 × 7 = 35.    3 × 5 = 15.     8 × 5 = 40.    5 × 9 = 45.
4 × 2 = 8.       5 × 2 = 10.       9 × 2 = 18.    2 × 5 = 10.   10 × 3 = 30.   10 × 5 = 50.   4 × 6 = 24.
10 × 0 = 10.   1 × 8 = 8.        2 × 3 = 6.        7 × 4 = 28.   6 × 6 = 36.    10 × 8 = 80.   3 × 9 = 27.

Question 2.
Complete the division facts.
100 ÷ 10 = ____ 16 ÷ 2 = ____ 25 ÷ 5 = _____
12 ÷ 2 = ____ 3 ÷ 1 = ____ 20 ÷ 2 = _____
Answer:
Division Facts:
100 ÷ 10 = 10.    16 ÷ 2 = 8.       25 ÷ 5 = 5.
12 ÷ 2 = 6.           3 ÷ 1 = 3.        20 ÷ 2 = 10.

Explanation:
Given Equations:
100 ÷ 10 = 10.
16 ÷ 2 = 8.
25 ÷ 5 = 5.
12 ÷ 2 = 6.
3 ÷ 1 = 3.
20 ÷ 2 = 10.

Question 3.
CHALLENGE Use what you know about basic fact strategies to solve these multiplication problems.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 2
Answer:
Multiplication Equations:
Bridges-in-Mathematics-Grade-3-Home-Connections-Answer-Key-Unit-3-Module-1-Multiplying & Dividing-3

Explanation:
GIven Equations:
24 × 5 = 120.
42 × 5 = 210.
329 × 0 = 0.
13 × 10 = 130.
1,946 × 1 = 1,946.
500 × 2 = 1,000.
25 × 6 = 150.

Question 4.
a. Would the product of 3,407 × 10 be odd or even? ____
Answer:
The product of 3,407 × 10 would be even not odd.

Explanation:
Multiplication:
3,407 × 10 = ????.
Bridges-in-Mathematics-Grade-3-Home-Connections-Answer-Key-Unit-3-Module-1-Multiplying & Dividing-4a
=> Multiplying 3,407 by 10, we get the product 34,070.

b. How do you know?
Answer:
I know it by doing multiplication.

Explanation:
Multiplication:
3,407 × 10 = ????.
Bridges-in-Mathematics-Grade-3-Home-Connections-Answer-Key-Unit-3-Module-1-Multiplying & Dividing-4a
=> Multiplying 3,407 by 10, we get the product 34,070.

Question 5.
Will is helping his mom get ready for a party. His mom wants Will to put flowers in jars to put on the tables. He needs to put 7 flowers in each jar. He has 45 flowers.

a. How many jars can he fill? Show all your work.
Answer:
Number of jars he can fill with flowers are 7.

Explanation:
Number of flowers in each jar he needs to put = 7.
Total number of flowers he has = 45.
Number of jars he can fill = Total number of flowers he has ÷ Number of flowers in each jar he needs to put
= 45 ÷ 7
= 6 quotient and 3 remainder.
= 7.

Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 3

b. How many flowers did Will have left over?
Answer:
Number of flowers will be left out 3 if he fills each jar with 7 flowers.

Explanation:
Number of flowers in each jar he needs to put = 7.
Total number of flowers he has = 45.
Number of jars he can fill = Total number of flowers he has ÷ Number of flowers in each jar he needs to put
= 45 ÷ 7
= 6 quotient and 3 remainder.
= 7.

Question 6.
Mai is buying gifts for her 4 friends. She wants to get each friend a bracelet that costs $4 and a mechanical pencil that costs $3.

a. How much money will she spend in all? Show all your work.
Answer:
Total amount spent by Mai = $48.

Explanation:
Number of friends Mai buying gifts = 4.
Cost of bracelet She wants to get each friend = $4.
Cost of mechanical pencil She wants to get each friend = $3.
Total amount spent by Mai = Number of friends Mai buying gifts × (Cost of bracelet She wants to get each friend + Cost of mechanical pencil She wants to get each friend)
= 4 × ($4 + $3)
= 4 × $12
= $48.

b. Write an equation to represent this problem. Use the letter m to stand for the amount of money Mai spent in all.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 4
Answer:
Equation:
Total amount spent by Mai (m) = Number of friends Mai buying gifts × (Cost of bracelet She wants to get each friend + Cost of mechanical pencil She wants to get each friend)
= 4 × ($4 + $3)
= $48.

Explanation:
Number of friends Mai buying gifts = 4.
Cost of bracelet She wants to get each friend = $4.
Cost of mechanical pencil She wants to get each friend = $3.
Total amount spent by Mai (m) = Number of friends Mai buying gifts × (Cost of bracelet She wants to get each friend + Cost of mechanical pencil She wants to get each friend)
= 4 × ($4 + $3)
= 4 × $12
= $48.

Question 7.
CHALLENGE Mai changed her mind and decided to get each of her 4 friends a comic book that cost $3.99 and an eraser that cost $9.94. How much money did she spend in all? Show all of your work.
Answer:
Total amount she spents in all = $55.72

Explanation:
Number of friends Mai buying gifts = 4.
Cost of a comic book = $3.99.
Cost of an eraser = $9.94.
Total amount she spents in all = Number of friends Mai buying gifts × (Cost of a comic book + Cost of an eraser)
= 4 × ($3.99 + $9.94)
= 4 × $13.93
= $55.72.

Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Session 3 Answer Key

Rounding to the Nearest Ten

You can use a number line to help round to the nearest ten. If a number is closer to the next larger multiple of 10, round up. If it is closer to the next smaller multiple of 10, round down.
If the digit in the ones place is 5 or higher, round up. If the digit in the ones place is less than 5, round down.
ex Round 127 to the nearest ten. Use the number line to help.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 5

Question 1.
Round each number to the nearest ten. Use the number line to help.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 6
Answer:
Rounded numbers to their nearest 10’s:
a. 78 – 80.
b. 75 – 80.
c. 74 – 70.

Explanation:
Given numbers:
a. 78 – closer to the next larger multiple of 10 – 80.
b. 75 – closer to the next larger multiple of 10 – 80.
c. 74 – closer to the next smaller multiple of 10 – 70.

Question 2.
Round each number to the nearest ten. Use the number line to help.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 7
Answer:
Rounded numbers to their nearest 10’s:
a. 267 – 270.
b. 262 – 260.
c. 265 – 260.

Explanation:
Given numbers:
a. 267 – closer to the next larger multiple of 10 –  270.
b. 262 – closer to the next smaller multiple of 10 – 260.
c. 265 – closer to the next larger multiple of 10 – 270.

Question 3.
Round each number to the nearest ten. (Look at the digit in the ones place. Think about a number line if it helps you.)
a. 43 ____

b. 85 ____

c. 18 ____

d. 282 ____

e. 617 ____

f. 539 ____
Answer:
Rounded numbers to their nearest 10’s:
a. 43 – 40.
b. 85 – 90.
c. 18 – 20.
d. 282 – 280.
e. 617 – 620.
f. 539 – 540.

Explanation:
Given numbers:
a. 43 – closer to the next smaller multiple of 10 – 40.
b. 85 – closer to the next larger multiple of 10 – 90.
c. 18 – closer to the next larger multiple of 10 – 20.
d. 282 – closer to the next smaller multiple of 10 – 280.
e. 617 – closer to the next larger multiple of 10 – 620.
f. 539 – closer to the next larger multiple of 10 – 540.

Question 4.
The third and fourth graders at Fernwood School are going on a field trip. They will fill 3 school buses. Each bus holds 52 passengers. How many people will be going on the field trip? Show your work.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 8
Answer:
Number of people will be going on the field trip = 156.

Explanation:
Number of school buses = 3.
Number of passengers each bus can hold = 52.
Number of people will be going on the field trip = Number of passengers each bus can hold × Number of school buses
= 52 × 3
= 156.

Question 5.
CHALLENGE Mr. Kelly bought 8 dozen hot dogs for the third grade picnic. His pet dog broke into the groceries and ate 14 hot dogs. If each picnic guest eats one hot dog, how many people can still have a hot dog? Show your work.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 9
Answer:
Number of people can still have a hot dog = 82.

Explanation:
Number of dozen hot dogs for the third grade picnic Mr. Kelly bought = 8.
=> 1 dozen = 12.
=> 8 dozens = 12 × 8 = 96.
Total number of hot dogs for the third grade picnic Mr. Kelly bought = 96.
Number of hot dogs her dog ate = 14.
If each picnic guest eats one hot dog.
=> Number of people can still have a hot dog = Total number of hot dogs for the third grade picnic Mr. Kelly bought  – Number of hot dogs her dog ate
= 96 – 14
= 82.

Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Session 2 Answer Key

Round & Round

Question 1.
Rounding numbers can help you make good estimates. Round each pair of numbers to the nearest ten and then add the rounded numbers to estimate the sum.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 10

a.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 11
Answer:
Bridges-in-Mathematics-Grade-3-Home-Connections-Answer-Key-Unit-3-Module-1-Multiplying & Dividing-Round & Round-1a

Explanation:
Given numbers:
168 + 122 = ???.
Round numbers to nearest ten:
168 – 170.
122 – 120.
Sum:
170 + 120 = 290.

b.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 12
Answer:
Bridges-in-Mathematics-Grade-3-Home-Connections-Answer-Key-Unit-3-Module-1-Multiplying & Dividing-Round & Round-1b

Explanation:
Given numbers:
147 + 618 = ???.
Round numbers to nearest ten:
147 – 150.
618 – 620.
Sum:
150 + 620 = 770.

Question 2.
Estimate for each story problem below. Explain your estimation using numbers, sketches, or words.

a. Ravi likes to ride on the merry-go-round. Each ride lasts for 49 seconds. If Ravi takes 2 rides, about how long does he spend on the merry-go-round?
Answer:
Time he spends on the merry-go-round = 98 seconds.

Explanation:
Number of seconds each ride lasts = 49.
Number of rides he takes = 2.
Time he spends on the merry-go-round = Number of seconds each ride lasts × Number of rides he takes
= 49 × 2
= 98 seconds.

b. Each ride on the merry-go-round costs 97 cents. If Ravi rides the merry-go-round 4 times, about how much does he have to pay?
Answer:
Amount of money he have to pay = 388 cents.

Explanation:
Cost of each ride on the merry-go-round = 97 cents.
Number of rides he takes = 4.
Amount of money he have to pay = Cost of each ride on the merry-go-round × Number of rides he takes
= 97 × 4
= 388 cents.

Show all your work when you solve these story problems.

Question 3.
Midge is a tiger shark and Bruce is a great white shark. Midge is 396 centimeters long and Bruce is 609 centimeters long. How many centimeters longer is Bruce than Midge?
Answer:
213 centimeters longer is Bruce than Midge.

Explanation:
Number of centimeters Midge = 396.
Number of centimeters Bruce = 609.
Difference:
Number of centimeters Bruce – Number of centimeters Midge
= 609 – 396
= 213.

Question 4.
Which equation does NOT describe the situation in problem 3?
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 13 609 – 396 = c
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 13 396 + 609 = c
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 13 396 + c = 609
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 13 609 – c = 396
Answer:
Equation does NOT describe the situation in problem 3:
609 – 396 = describes.
396 + 609 = doesnot describe.
396 + c = 609 – doesnot describe.
609 – c = 396 – doesnot describe.

Explanation:
Answer 3:
Number of centimeters Midge = 396.
Number of centimeters Bruce = 609.
Difference:
Number of centimeters Bruce – Number of centimeters Midge
= 609 – 396
= 213.
Given Equations:
609 – 396 = describes.
396 + 609 = doesnot describe.
396 + c = 609 – doesnot describe.
609 – c = 396 – doesnot describe.

Question 5.
CHALLENGE The greater roadrunner (a bird that runs better than it flies) can run 16 miles per hour. A frightened ostrich can run 3 times faster.

a. How fast can a frightened ostrich run?
Answer:
Number of miles a frightened ostrich runs 48 per hour.

Explanation:
Number of miles a bird runs = 16 per hour.
A frightened ostrich can run 3 times faster.
=> Number of miles a frightened ostrich runs = 3 × Number of miles a bird runs
= 3 × 16
= 48 per hour.

b. How far can a frightened ostrich run in half an hour?
Answer:
Number of miles a frightened ostrich runs in half an hour = 24.

Explanation:
Number of miles a bird runs = 16 per hour.
A frightened ostrich can run 3 times faster.
=> Number of miles a frightened ostrich runs = 3 × Number of miles a bird runs
= 3 × 16
= 48 per hour.
=> Number of miles a frightened ostrich runs in half an hour = Number of miles a frightened ostrich runs in an hour ÷ 2
= 48 ÷ 2
= 24.

c. Fill in the boxes to complete an equation to represent problem 5b.
Bridges in Mathematics Grade 3 Home Connections Unit 3 Module 1 Answer Key 14
Answer:
An equation to represent problem 5b is  16 × 3 ÷ 2 = 24 miles.

Explanation:
Number of miles a bird runs = 16 per hour.
A frightened ostrich can run 3 times faster.
=> Number of miles a frightened ostrich runs = 3 × Number of miles a bird runs
= 3 × 16
= 48 per hour.
=> Number of miles a frightened ostrich runs in half an hour = Number of miles a frightened ostrich runs in an hour ÷ 2
= 48 ÷ 2
= 24.

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