 # Addition of Metric Measures – Methods, Examples | How to Add Metric Measures?

Wondering how to add metric measures, then you have reached a safe place that will let you know how to add the metric measures and also explain the steps and detailed procedure of adding those numbers. The addition of metric measures is useful in our daily life and this adding of metric measures is similar to the addition of ordinary numbers.

We will arrange them in columns according to their units and we will add them. Before adding metric measures we need to know about metric measures and also about converting them from one unit to another unit.

## How to Add Metric Measures?

The Addition of metric measures is similar to the adding of ordinary numbers. Adding of these mixed measures can be done in two ways, one is to convert all the mixed measure into one unit and adding them, to do this we have known about converting the units and you can learn by referring to our earlier articles. The other way is to add like units by placing the digits in columns and adding. To understand in detail we will go with one example which we will solve in two methods.

Example:
Add 5 km 4 hm 8 m 3 mm and 8 km 9 hm 6 m 3 mm.
Solution:
Method 1: Place the given two digits in columns and add them usually. Therefore the result of addition is 14 km 4 hm 4 m 6 mm.
Method 2:
Convert the given two numbers into same unit that is we will convert them into km.
we know that 1000000 mm = 1 km, 1000 m = 1 km, 10 hm = 1 km

5 km 4 hm 8 m 3 mm = 5 km + $$\frac { 4 }{ 10 }$$ km + $$\frac { 8 }{ 100 }$$ km +$$\frac { 3 }{ 1000000}$$
= 5 km + 0.4 km + 0.08 km + 0.000003 km
= 5.480003 km.
8 km 9 hm 6 m 3 mm = 8km + $$\frac { 9 }{ 10 }$$ km+ $$\frac { 6 }{ 100}$$ km+$$\frac { 3}{ 1000000 }$$ km
= 8 km + 0.9 km + 0.06 km + 0.000003 km
= 8.960003 km
Now by adding them we get
5.480003 + 8.960003 = 14.440006 km
Therefore the result of addition is 14.440006 km.

### Addition of Metric Measures Examples

Here are some examples involving the addition of metric measures of length, mass, and capacity. We will be solving these examples in the first method only, which will make students understand easily about the concept.
Example 1:
Add 6 kg 2 hg 0 dag 5 g 0 dg 7 cg and 2 kg 5 hg 6 dag 3 g 0 dg 2 cg.
Solution:
Arrange the given numbers in the column vertically and add them from right to left. Therefore the result of the addition is 8 kg 7 hg 6 dag 8 g 0 dg 9 cg.

Example 2:
Add 9 km 6 hm 5 dcm 4 m 1 dm 2 cm and 4 km 0 hm 3 dcm 5 m 7 dm 2 cm.
Solution:
Arrange the given numbers in the column vertically and add them from right to left. Therefore, the addition is 13 km 6 hm 8 dcm 9 m 8 dm 4 cm.

Example 3:
Add 3 kl 6 hl 0 dal 7 l 5 dl 1 cl and 5 kl 6 hl 7 dal 0 l 4 dl 1 cl.
Solution:
Arrange the given numbers in the column vertically and add them from right to left. Therefore, the addition is 8 kl 12 hl 7 dal 7 l 9 dl 2 cl.

Example 4:
Annie has 6 kg 450 g of sugar in a bag and she added more than 8 hg 320 g in it. How much amount of sugar is in the bag?
Solution:
Given
weight of sugar in bag = 6 kg 450 g
weight of sugar she added = 8 hg 320 g
Total weight of the sugar in bag = weight of sugar in bag + weight of sugar she added Therefore, Amount of the sugar in the bag is 6 kg 8 hg 770 g.

Example 5:
Charlie bought 5 kl 65 l of milk in one shop and 60 hl and 56 dal of milk in another shop. How much amount of milk he has?
Solution:
Given
Amount of milk he bought in the first shop = 5 kl 65 l
Amount of milk he bought in the second shop = 60 hl 56 dal
The total amount of milk = Amount of milk he bought in the first shop + Amount of milk he bought in the second shop Therefore, the total amount of milk he bought = 5 kl 60 hl 56 dal and 65l.

Example 6:
Meera traveled 67 km 50 dcm towards the east and 34 km 500 m towards the northeast. How much distance did she travel in total?
Solution:
Given
Distance traveled towards east = 67 km 50 dcm
Distance traveled towards north-east = 34 km 500 m
Total distance traveled by Meera is = Distance traveled towards east  + Distance traveled towards north-east.
= 67 km 50 dcm + 34 km 500 m Therefore, the total distance she traveled is 101 km 50 dcm 500m.

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