180 Days of Math for Third Grade Day 161 Answers Key

By accessing our 180 Days of Math for Third Grade Answers Key Day 161 regularly, students can get better problem-solving skills.

180 Days of Math for Third Grade Answers Key Day 161

Directions: Solve each problem.

Question 1.
202 + 37 = 180 Days of Math for Third Grade Day 161 Answers Key 1
Answer:
202 + 37 = 239
By adding 202 with 37 we get 239.

Question 2.
4 × 8 = 180 Days of Math for Third Grade Day 161 Answers Key 1
Answer:
4 × 8 = 32
Multiplying 4 with 8 then we get 32.

Question 3.
4 × 80 = 180 Days of Math for Third Grade Day 161 Answers Key 1
Answer:
4 × 80 = 320
Multiplying 4 with 80 = 320.

Question 4.
27 ÷ 3 = 180 Days of Math for Third Grade Day 161 Answers Key 1
Answer:
27 ÷ 3 = 9
Dividing 27 with 3 then we get 9.

Question 5.
Write 264 in expanded notation.
Answer:
264 in the expanded notation is 200 + 60 + 4.
Here we have 2 hundred, 6 tens and 4 ones.

Question 6.
2,000 + 180 Days of Math for Third Grade Day 161 Answers Key 1 + 6 = 2056
Answer:
2000 + 50 + 6 = 2056
2 thousands, 5 tens, 6 ones.

Question 7.
True or false?
A playground has an area of more than 1 m2.
Answer:
True
A playground has an area of more than 1 m2 because 1 m2 is too small to play the games.

Question 8.
Write 9 minutes past 10 on the clock.
180 Days of Math for Third Grade Day 161 Answers Key 2
Answer:
180-Days-of-Math-for-Third-Grade-Day-161-Answers-Key-2
9 minutes past on 10 is 10 : 9

Question 9.
Complete the chart.
180 Days of Math for Third Grade Day 161 Answers Key 3

Number of Sides 5
Number of Angles 5
Number of Lines of Symmetry 5
Name of Shape pentagon

Answer:
The number of sides in a pentagon is 5.
The number of angles in a pentagon is 5.
The number of lines of symmetry is 5.
The name of the shape is the pentagon.

Question 10.
If you multiply me by 10, you get 120. What number am I?
Answer:
10 × 12 = 120.
I am 12 multiply by me by 10 you get 120.

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