180 Days of Math for Third Grade Day 103 Answers Key

By accessing our 180 Days of Math for Third Grade Answers Key Day 103 regularly, students can get better problem-solving skills.

180 Days of Math for Third Grade Answers Key Day 103

Directions: Solve each problem.

Question 1.
56 – 29 = 180 Days of Math for Third Grade Day 103 Answers Key 1
Answer: 27
Explanation:
By performing the subtraction for two given numbers we can find the difference.

Question 2.
180 Days of Math for Third Grade Day 103 Answers Key 2
Answer: 320
180-Days-of-Math-for-Third-Grade-Day-103-Answers-Key-2
Explanation:
By performing the multiplication operation we can find the product of 80 and 4.

Question 3.
9 × 6 = 180 Days of Math for Third Grade Day 103 Answers Key 1
Answer: 54
Explanation:
By performing the multiplication operation we can find the product of 9 and 6.
9 × 6 = 54

Question 4.
25 ÷ 5 = 180 Days of Math for Third Grade Day 103 Answers Key 1
Answer: 5
By dividing 25 by 5 we get the quotient as 5 and the remainder as 0.

Question 5.
Is there enough money shown to buy something that costs 51 ¢?
Circle:
yes
no
180 Days of Math for Third Grade Day 103 Answers Key 3
Answer:
The above coin is a quarter dollar.
1 quarter dollar = 25¢
25¢ + 25¢ + 25¢ = 75¢
Thus you have enough money to buy something that costs 51 ¢.
So, the answer is yes.

Question 6.
42 180 Days of Math for Third Grade Day 103 Answers Key 1 6 = 7
Answer: division
42 ÷ 6 = 7

Question 7.
Circle the solid that has less volume.
180 Days of Math for Third Grade Day 103 Answers Key 4
Answer: Figure B has less volume.
180-Days-of-Math-for-Third-Grade-Day-103-Answers-Key-7

Question 8.
Is the mass of a nail more or less than one kilogram?
Answer: The mass of a nail is less than one kilogram.

Question 9.
How many children chose the slide as their favorite?

Favorite Playground Equipment
180 Days of Math for Third Grade Day 103 Answers Key 5
Answer:
1 emoji = 5 children
Slide = 5 emojis
5 × 5 = 25 children
Thus 25 children chose the slide as their favorite.

Question 10.
What 3-digit numbers that have 7 in the hundreds place can be made using each digit 7, 4, 9, and 6 only once?
Answer:
749
6794

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