180 Days of Math for Sixth Grade Day 93 Answers Key

By accessing our 180 Days of Math for Sixth Grade Answers Key Day 93 regularly, students can get better problem-solving skills.

180 Days of Math for Sixth Grade Answers Key Day 93

Directions: Solve each problem.

Question 1.
74 – 39 = ___________
Answer:
180 Days of Math for Sixth Grade Answers Key Day 93_1

Question 2.
180 Days of Math for Sixth Grade Day 93 Answers Key 1
Answer:
180-Days-of-Math-for-Sixth-Grade-Day-93-Answers-Key-2

Question 3.
Divide 72 by -8.
Answer:
72/8 = 9
We observe a negative sign in the divisor so the obtained result is -9

Question 4.
Round 4,529 to the nearest hundred.
Answer: 4529 to the nearest hundred is 4500.

Question 5.
How many eighths are in 1\(\frac{1}{8}\)?
Answer:
1\(\frac{1}{8}\) = \(\frac{9}{8}\)
There are 9 eighths in 1\(\frac{1}{8}\)

Question 6.
(5 + 2)2 – 32 = ____________
Answer:
(5 + 2)2 – 32 = 7² – 3²
= 49 – 9 = 40

Question 7.
14 + 180 Days of Math for Sixth Grade Day 93 Answers Key 2 = 40 – 5
Answer:
Let the unknown value be x.
14 + x = 40 – 5
14 + x = 35
x = 35 – 14
x = 21

Question 8.
Write the expression for d less than 12.
Answer: d – 12

Question 9.
How many kilograms are in 4,000 grams?
Answer:
Convert from grams to kilograms
1 kg = 1000 grams
4000 grams = 4 kgs

Question 10.
How many axes of symmetry does the shape have?
180 Days of Math for Sixth Grade Day 93 Answers Key 3
Answer: The shape has 1 axes of symmetry.

Question 11.
180 Days of Math for Sixth Grade Day 93 Answers Key 4
If there is a $3.00 toll to cross the bridge, how much money was collected on Monday?
Answer: 12 × $3 = $ 36.00

Question 12.
Kent can swim 100 m in 50 seconds. How long will it take him to swim 300 m?
Answer:
100 m = 50 seconds
300 m = 3 × 50 = 150 seconds

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