180 Days of Math for Sixth Grade Day 83 Answers Key

By accessing our 180 Days of Math for Sixth Grade Answers Key Day 83 regularly, students can get better problem-solving skills.

180 Days of Math for Sixth Grade Answers Key Day 83

Directions: Solve each problem.

Question 1.
180 Days of Math for Sixth Grade Day 83 Answers Key 1
Answer:
180-Days-of-Math-for-Sixth-Grade-Day-83-Answers-Key-1

Question 2.
72 × 100 = __________
Answer: 72 × 100 = 7200

Question 3.
What is the quotient when 824 is divided by 7?
Answer: 824 ÷ 7 = 117.7

Question 4.
Round 45,678 to the nearest thousand.
Answer: The number 45,678 to the nearest thousand is 46,000.

Question 5.
\(\frac{1}{8}\) – \(\frac{4}{8}\) = ___________
Answer:
The denominators of both the fractions are same so we can subtract the numerators.
\(\frac{1}{8}\) – \(\frac{4}{8}\) = \(\frac{1-4}{8}\) = –\(\frac{3}{8}\)

Question 6.
62 + 3 × 5 = __________
Answer:
62 + 3 × 5
36 + 3 × 5
36 + 15 = 51

Question 7.
180 Days of Math for Sixth Grade Day 83 Answers Key 2
Answer: 0.75 = \(\frac{3}{4}\)

Question 8.
Find q.
\(\frac{50}{q}\) = 25
q = ___________
Answer:
Given,
\(\frac{50}{q}\) = 25
50 = 25 × q
50/25 = q
q = 2

Question 9.
How many minutes are from 5:32 P.M. to 6:19 P.M.?
Answer:
6 hour 19 mins
5 hour 32 mins

5 hour 79 mins
5 hour 32 mins
0 hour 47 mins
There are 47 minutes from 5:32 P.M. to 6:19 P.M.

Question 10.
Draw the cross-section for the solid.
180 Days of Math for Sixth Grade Day 83 Answers Key 3
Answer: The cross-section for the solid is pentagon.

Question 11.
180 Days of Math for Sixth Grade Day 83 Answers Key 4
On which date did 50 students travel?
Answer:

Question 12.
Jerry rents a movie once a month. It costs $3.00 to rent a movie. How much does Jerry spend in 1 year on rentals?
Answer:
Given,
Jerry rents a movie once a month.
It costs $3.00 to rent a movie.
$3.00 × 12 = $36.00

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