180 Days of Math for Sixth Grade Day 51 Answers Key

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180 Days of Math for Sixth Grade Answers Key Day 51

Directions Solve each problem.

Question 1.
56 – 39 = ___
Answer:
56-39 = 17.

Explanation:
By subtracting 39 in 56 we will get 17.

Question 2.
9 × 40 = ______
Answer:
9 × 40 = 360.

Explanation:
By multiplying 9 and 40 we will get 9 × 40 = 360.

Question 3.

Answer:
42÷7 = 6.

Explanation:
By dividing 42 by 7 we will get 42÷7 = 6.

Question 4.
What is the value of the digit 9 in 4,729?
_______________________
Answer:
9 is in one’s place.

Explanation:
The value of the digit 9 in 4,729 is one’s place.

Question 5.
Is 1\(\frac{2}{3}\) less than or greater than 1\(\frac{3}{4}\)?
_______________________
Answer:
1\(\frac{2}{3}\) less than 1\(\frac{3}{4}\).

Explanation:
GIven 1\(\frac{2}{3}\) which is \(\frac{5}{3}\) and in decimal 1.67 and 1\(\frac{3}{4}\) which is \(\frac{7}{4}\) and in decimals it will be 1.75. So 1\(\frac{2}{3}\) is less than 1\(\frac{3}{4}\).

Question 6.
4 + 2 • 5 + 3 = ____
Answer:
4 + 2 • 5 + 3 = 48.

Explanation:
Given the expression is 4 + 2 • 5 + 3, so
4 + 2 • 5 + 3 = 6 × 8
= 48.

Question 7.
% of 80 is 20.
Answer:
25% of 80 is 20.

Explanation:
Let the missing % be X, so X% of 80 is 20
X% × 80 = 20
\(\frac{X}{100}\) × 80 = 20
\(\frac{4X}{5}\) = 20
4X = 20×5
X = \(\frac{20×5}{4}\)
= 25.

Question 8.
Solve for f. f + \(\frac{3}{8}\) = \(\frac{5}{8}\) f = ___
Answer:
f = \(\frac{1}{4}\).

Explanation:
Given that f + \(\frac{3}{8}\) = \(\frac{5}{8}\),
f = \(\frac{5}{8}\) – \(\frac{3}{8}\)
= \(\frac{5-3}{8}\)
= \(\frac{2}{8}\)
= \(\frac{1}{4}\).

Question 9.
How many pints are in a quart?
_______________________
Answer:
2 pints in 1 quarts.

Explanation:
There are 2 pints in 1 quarts.

Question 10.
Which line is perpendicular to line B?
_______________________

Answer: line G is perpendicular to line B.

Question 11.
Record the data in the table. Trish has 2 brothers and 1 sister. Max doesn’t have any siblings. Melissa has 2 brothers. Allison has 1 sister. Trent has a brother and a sister.

Answer:

Child’s Name	Brothers	Sisters
Trish	2	1
Max	0	0
Melissa	2	0
Allison	0	1
Trent	1	1

Question 12.
A farmer sold 250 of his sheep, bought 35 more sheep, and then bought 68 more sheep. After 3 died, he sold another 260. If he now has 190 sheep, how many sheep did he have at the beginning?
_______________________
Answer:
The sheep at the beginning is 600.

Explanation:
Let the sheep at the beginning be X, As he sold 250 sheep and bought 35 more sheep and then bought 68 more sheep. So X-250+35+68 which is X-147. After that 3 died, he sold another 260 which is X-147-3-260 which is X-410. As he now has 190 sheep, so X-410 = 190,
X = 190+410,
= 600.
So the sheep at the beginning is 600.