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## 180 Days of Math for Sixth Grade Answers Key Day 51

**Directions Solve each problem.**

Question 1.

56 – 39 = ___

Answer:

56-39 = 17.

Explanation:

By subtracting 39 in 56 we will get 17.

Question 2.

9 × 40 = ______

Answer:

9 × 40 = 360.

Explanation:

By multiplying 9 and 40 we will get 9 × 40 = 360.

Question 3.

Answer:

42÷7 = 6.

Explanation:

By dividing 42 by 7 we will get 42÷7 = 6.

Question 4.

What is the value of the digit 9 in 4,729?

_______________________

Answer:

9 is in one’s place.

Explanation:

The value of the digit 9 in 4,729 is one’s place.

Question 5.

Is 1\(\frac{2}{3}\) less than or greater than 1\(\frac{3}{4}\)?

_______________________

Answer:

1\(\frac{2}{3}\) less than 1\(\frac{3}{4}\).

Explanation:

GIven 1\(\frac{2}{3}\) which is \(\frac{5}{3}\) and in decimal 1.67 and 1\(\frac{3}{4}\) which is \(\frac{7}{4}\) and in decimals it will be 1.75. So 1\(\frac{2}{3}\) is less than 1\(\frac{3}{4}\).

Question 6.

4 + 2 • 5 + 3 = ____

Answer:

4 + 2 • 5 + 3 = 48.

Explanation:

Given the expression is 4 + 2 • 5 + 3, so

4 + 2 • 5 + 3 = 6 × 8

= 48.

Question 7.

% of 80 is 20.

Answer:

25% of 80 is 20.

Explanation:

Let the missing % be X, so X% of 80 is 20

X% × 80 = 20

\(\frac{X}{100}\) × 80 = 20

\(\frac{4X}{5}\) = 20

4X = 20×5

X = \(\frac{20×5}{4}\)

= 25.

Question 8.

Solve for f. f + \(\frac{3}{8}\) = \(\frac{5}{8}\) f = ___

Answer:

f = \(\frac{1}{4}\).

Explanation:

Given that f + \(\frac{3}{8}\) = \(\frac{5}{8}\),

f = \(\frac{5}{8}\) – \(\frac{3}{8}\)

= \(\frac{5-3}{8}\)

= \(\frac{2}{8}\)

= \(\frac{1}{4}\).

Question 9.

How many pints are in a quart?

_______________________

Answer:

2 pints in 1 quarts.

Explanation:

There are 2 pints in 1 quarts.

Question 10.

Which line is perpendicular to line B?

_______________________

Answer: line G is perpendicular to line B.

Question 11.

Record the data in the table. Trish has 2 brothers and 1 sister. Max doesn’t have any siblings. Melissa has 2 brothers. Allison has 1 sister. Trent has a brother and a sister.

Answer:

Child’s Name | Brothers | Sisters |

Trish | 2 | 1 |

Max | 0 | 0 |

Melissa | 2 | 0 |

Allison | 0 | 1 |

Trent | 1 | 1 |

Question 12.

A farmer sold 250 of his sheep, bought 35 more sheep, and then bought 68 more sheep. After 3 died, he sold another 260. If he now has 190 sheep, how many sheep did he have at the beginning?

_______________________

Answer:

The sheep at the beginning is 600.

Explanation:

Let the sheep at the beginning be X, As he sold 250 sheep and bought 35 more sheep and then bought 68 more sheep. So X-250+35+68 which is X-147. After that 3 died, he sold another 260 which is X-147-3-260 which is X-410. As he now has 190 sheep, so X-410 = 190,

X = 190+410,

= 600.

So the sheep at the beginning is 600.