180 Days of Math for Sixth Grade Day 111 Answers Key

By accessing our 180 Days of Math for Sixth Grade Answers Key Day 111 regularly, students can get better problem-solving skills.

180 Days of Math for Sixth Grade Answers Key Day 111

Directions: Solve each problem.

Question 1.
200 – 94 = ___________
Answer:
200
– 94
106

Question 2.
10 • 61 = _________
Answer: 10 • 61 = 610

Question 3.
180 Days of Math for Sixth Grade Day 111 Answers Key 1
Answer: 23 ÷ 5 = 4.6

Question 4.
What is the value of the digit 2 in the number 425,611?
Answer: The value of digit 2 in the number 425,611 is 20,000.

Question 5.
True or false? 0.75 > 0.60
Answer: 0.75 > 0.60 is true

Question 6.
(5 × 2)2 = ____________
Answer:
5 × 2 = 10
10² = 100

Question 7.
81 – 25 = 180 Days of Math for Sixth Grade Day 111 Answers Key 2 + 3
Answer:
Let the unknown value be x.
81 – 25 = x + 3
56 = x + 3
x = 56 – 3
x = 53

Question 8.
Find r.
r + 5.6 = 10.8
r = ___________
Answer:
r + 5.6 = 10.8
r = 10.8 – 5.6
r = 5.2

Question 9.
How many milliliters are in 3\(\frac{1}{2}\) liters?
Answer:
1 liter = 1000 milliliters
3\(\frac{1}{2}\) liters = 3\(\frac{1}{2}\) liters × 1000 = 3500 milliliters

Question 10
Name the shape that is located at (C, 3).
180 Days of Math for Sixth Grade Day 111 Answers Key 3
Answer: The shape of (C, 3) is parallelogram.

Question 11.
Record the data in the horizontal bar graph. California had 8 inches of rain. Oregon had 10 inches of rain. Washington had 14 inches of rain.
180 Days of Math for Sixth Grade Day 111 Answers Key 4
Answer:
180 Days of Math for Sixth Grade Answers Key Day 111_11

Question 12.
Your chances of winning a prize in a raffle are \(\frac{1}{50}\). If 1,000 tickets are sold, how many people will win prizes if each person can only win one prize?
Answer: 1000 × \(\frac{1}{50}\) = 20

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