180 Days of Math for Fourth Grade Day 139 Answers Key

By accessing our 180 Days of Math for Fourth Grade Answers Key Day 139 regularly, students can get better problem-solving skills.

180 Days of Math for Fourth Grade Answers Key Day 139

Directions: Solve each problem.

Question 1.
27 + 15 = _________
Answer:
180 Days of Math for Fourth Grade Answers Key Day 139_1
Thus the addition of 27 and 15 is 42.

Question 2.
\(\frac{1}{8}\) of 40 is ___________.
Answer:
\(\frac{1}{8}\) × 40 = 5

Question 3.
50 ÷ 10 = ___________
Answer:
180 Days of Math for Fourth Grade Answers Key Day 139_3
The quotient is 5 and the remainder is 0.

Question 4.
180 Days of Math for Fourth Grade Day 139 Answers Key 1
Answer:
180 Days of Math for Fourth Grade Answers Key Day 139_4
The quotient is 4 and the remainder is 2.

Question 5.
Round 4,737 to the nearest thousand.
Answer: 4737 to the nearest thousand is 5000.

Question 6.
7 + 7 + 7 + 7 + 180 Days of Math for Fourth Grade Day 139 Answers Key 2 = 5 × 7
Answer:
Given,
7 + 7 + 7 + 7 + 180 Days of Math for Fourth Grade Day 139 Answers Key 2 = 5 × 7
Let the missing number be x.
7 + 7 + 7 + 7 + x = 5 × 7
28 + x = 35
x = 35 – 28
x = 7
Thus the missing number is 7.

Question 7.
How many days are in January? _________
May? _________
August? __________
Answer:
There are 31 days in January
There are 31 days in May
There are 31 days in August

Question 8.
10 mm = ___________ cm
Answer:
We have to convert from millimeters to centimeters.
1 cm = 10 mm

Question 9.
Label with reflection, rotation, or translation.
180 Days of Math for Fourth Grade Day 139 Answers Key 3
Answer: translation

Question 10.
Draw 9 triangles. Color \(\frac{2}{3}\) of them yellow. Color the rest blue. How many are blue?
Answer:
180 Days of Math for Fourth Grade Answers Key Day 139_10
Among 9 triangles 6 are yellow and 3 are blue color

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